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dimulka [17.4K]
3 years ago
13

12.

Physics
1 answer:
myrzilka [38]3 years ago
7 0

Answer:

3.68 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 9.4 ms¯¹

Maximum height (h) reached = 12 m

Final velocity (v) = 0 (at maximum height)

Acceleration of free fall (g) =?

v² = u² – 2gh (since the rock is going against gravity)

0 = 9.4² – 2 × g × 12

0 = 88.36 – 24g

Collect like terms

0 – 88.36 = –24g

–88.36 = –24g

Divide both side by –24

g = –88.36 / –24

g = 3.68 m/s²

Thus, the acceleration of free fall near the surface of Mar is 3.68 m/s².

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Explain how Rutherfords' gold foil experiment explains how this experiment confirms the nuclear model of the atom and the idea t
alekssr [168]

Explanation:

When Rutherford did the Gold Foil experiment, he expected that most of his alpha particles will go straight through, without any major deflections. He noticed that, during the experiment, most alpha particles went straight through, but was surprised to see that some got deflected by major angles. So he came up with a theory which states that every atom has got a nucleus, and also stated that most parts of the atom are empty, as most of the particles went through.

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6 0
4 years ago
You fill two balloons with gas, one with hydrogen and one with carbon dioxide. You hold a match to each balloon. The hydrogen ba
miv72 [106K]

Answer:E. Hydrogen was able to participate in an exergonic reaction and carbon dioxide couldn't

Explanation:

An exergonic reaction releases energy to the environment. The combustion of hydrogen contained in the balloon is a chemical reaction. The reaction can take place because hydrogen combines with oxygen in air, that is, the gas is combustible. CO2 does not support combustion, it does not combine with oxygen in air and it is also denser than air, hence does not participate in the exergonic reaction.

4 0
3 years ago
Determine the voltage ratings of the high-and-low voltage windings for this connection and the MVA rating of the autotransformer
SIZIF [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The High Voltage Rating for Auto - Transformer is 86kV

The  Low Voltage Rating for Auto - Transformer is 78kV

The MVA rating is 268.75MVA

b

The efficiency is 99.4%

Explanation:

From the question  we are given are given that

 The transformer has Mega Volt Amp rating of 25MVA

                          The frequency is 60-Hz

                           Voltage rating 8.0kV : 78kV

   The short circuit test gives : 453kV,321A,77.5kW

   The open circuit test gives : 8.0kV, 39.6A, 86.2kW

This can be represented on a diagram shown on the second uploaded image

From this diagram we can deduce that the The High Voltage Rating for Auto - Transformer is 86kV and the  Low Voltage Rating for Auto - Transformer is 78kV

 Now to obtain the current flowing through the 8kV  coil in the Auto-transformer we have

             \frac{25 \ Mega \ Volt\ Ampere }{8\ Kilo Volt}

The volt will cancel each other

             \frac{25*10^6}{8*10^3} =  3125\ A

 Now to obtain the required MVA rating we would multiply the value of Power obtained during the open circuit test by the value of the current calculated.we are making use of the power obtain during open circuit testing because the transformer at this point is not under any load.

MVA \ rating = (86*10^3)(3125) =268.75

We need to understand that Iron losses is due to open circuit test which has power = 86.2kW

While copper loss is due to short circuit test which has power = 77.5kW

The the current flowing through the secondary coil I_2 as shown in the circuit diagram can be obtained as

       I_2 = \frac{25*10^6}{78*10^3} =320.52 A \approx 321

Now the efficiency can be obtained as thus

           \frac{(operational \ MVA )*(Power factor \pf))}{(operational\  MVA (power factor pf) + copper loss + Iron loss)}*\frac{100}{1}

             =99.941%

8 0
3 years ago
A gas has a pressure of 48atm in a 15.5L container. It was found that at 25∘C the gas occupied a volume of 25L and had a pressur
EleoNora [17]

Answer:

130.165636364°C

Explanation:

P = Pressure

V = Volume

n = Number of moles

R = Gas constant = 0.082 L atm/mol K

From ideal gas law we have

PV=nRT\\\Rightarrow n=\dfrac{PV}{RT}\\\Rightarrow n=\dfrac{22\times 25}{0.082\times (25+273.15)}\\\Rightarrow n=22.496451696\ moles

PV=nRT\\\Rightarrow T=\dfrac{PV}{nR}\\\Rightarrow T=\dfrac{48\times 15.5}{22.496451696\times 0.082}\\\Rightarrow T=403.315636364\ K

The initial temperature is 403.315636364-273.15=130.165636364\ ^{\circ}C

3 0
4 years ago
Whoever answers correctly gets brainlist!
UNO [17]

Infared = used by police

gamma = short wavelength

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3 years ago
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