The atoms undergo a phase called radioactive decay
Answer:
The acceleration produced is ![0.209 m/s^{2}](https://tex.z-dn.net/?f=0.209%20m%2Fs%5E%7B2%7D)
Explanation:
By the second law of Newton, the force F is equal to:
F = ma
Where m is the mass of the object and a is the acceleration produced. So if The force gives the standard 1 kg mass an acceleration of 1.00 m/s2, that means that the force apply on A and B is equal to:
F = (1Kg) * (1.00m/s2) = 1 N
Then, if this force on A produce an acceleration of 0.530
, the mass of A is:
![F = m_A*a_A \\1 N = m_A* (0.530 m/s^{2} )\\\frac{1N}{0.530m/s^{2} } =m_A\\\\1.887Kg = m_A](https://tex.z-dn.net/?f=F%20%3D%20m_A%2Aa_A%20%5C%5C1%20N%20%3D%20m_A%2A%20%280.530%20m%2Fs%5E%7B2%7D%20%29%5C%5C%5Cfrac%7B1N%7D%7B0.530m%2Fs%5E%7B2%7D%20%7D%20%3Dm_A%5C%5C%5C%5C1.887Kg%20%3D%20m_A)
At the same way, if this force on B produce an acceleration of 0.344
, the mass of B is:
![F = m_B*a_B \\1 N = m_B* (0.344 m/s^{2} )\\\frac{1N}{0.344m/s^{2} } =m_B\\\\2.907Kg = m_B](https://tex.z-dn.net/?f=F%20%3D%20m_B%2Aa_B%20%5C%5C1%20N%20%3D%20m_B%2A%20%280.344%20m%2Fs%5E%7B2%7D%20%29%5C%5C%5Cfrac%7B1N%7D%7B0.344m%2Fs%5E%7B2%7D%20%7D%20%3Dm_B%5C%5C%5C%5C2.907Kg%20%3D%20m_B)
Therefore, if they are attached and the same force is applied, the acceleration is:
![F=(m_A+m_B)*a\\1N=(1.887Kg + 2.907Kg)*a\\1N = 4.794 Kg *a\\\frac{1N}{4.794Kg}=a\\ 0.209 m/s^{2} =a](https://tex.z-dn.net/?f=F%3D%28m_A%2Bm_B%29%2Aa%5C%5C1N%3D%281.887Kg%20%2B%202.907Kg%29%2Aa%5C%5C1N%20%3D%204.794%20Kg%20%2Aa%5C%5C%5Cfrac%7B1N%7D%7B4.794Kg%7D%3Da%5C%5C%200.209%20m%2Fs%5E%7B2%7D%20%3Da)