Which ecosystem contains 32% of the world's producers

The engine starter and a headlight of a car are connected in parallel to the 12.0-V car battery. In this situation, the headligh

stepladder [879]

Answer:

The total power they will consume in series is approximately 2.257 W

Explanation:

The connection arrangement of the headlight and the engine starter = Parallel to the battery

The voltage of the battery, V = 12.0 V

The power at which the headlight operates in parallel, $P_{headlight}$ = 38 W

The power at which the kick starter operates in parallel, $P_{kick \ starter}$ = 2.40 kW

We have;

P = V²/R

Where;

R = The resistance

V = The voltage = 12 V (The voltage is the same in parallel circuit)

For the headlight, we have;

R₁ = V²/ $P_{headlight}$ = 12²/38 = 72/19

R₁ = 72/19 Ω

For the kick starter, we have;

R₂ = V²/ $P_{kick \ starter}$ = 12²/2.4 = 60

R₂ = 60 Ω

When the headlight and kick starter are rewired to be in series, we have;

Total resistance, R = R₁ + R₂

Therefore;

R = ((72/19) + 60) Ω = (1212/19) Ω

The current flowing, I = V/R

∴ I = 12 V/(1212/19) Ω = (19/101) A

We note that power, P = I²R

In the series connection, we have;

$P_{headlight}$ = I² × R₁

∴ $P_{headlight}$ = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W

The power at which the headlight operates in series, $P_{headlight, S}$ ≈ 0.134 W

$P_{kick \ starter}$ = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W

The power at which the kick starter operates in series, $P_{kick \ starter, S}$ ≈ 2.123 W

The total power they will consume, $P_{Total}$ = $P_{headlight, S}$ + $P_{kick \ starter, S}$

Therefore;

$P_{Total}$ ≈ 0.134 W + 2.123 W = 2.257 W

4 0

3 years ago

A shot-putter exerts an unbalanced force of 140 N on a shot giving it an

vekshin1

Answer:

7.37 kg

Explanation:

By Newtons Second Law of Unbalanced Forces

Force = Mass × Acceleration

140N = Mass × 19m/s^2

Mass = 140N / 19m/s^2

= 7.37 kg

8 0

3 years ago

Which statment about scientific knoledge is false

belka [17]

The phrase "scientific knoledge" in the question is spelled correctly.

6 0

2 years ago

Read 2 more answers

A machine can never be 100% efficient because some work is always lost due to which factor?

Pachacha [2.7K]

Answer:

A. can never be efficient due to friction

8 0

3 years ago

Read 2 more answers

A particle with a positive charge q is moving in the positive x direction with velocity of magnitude v0. If there were an electr

salantis [7]

Answer:

First, let's define the coordinate axes: positive x direction is to the right, positive y direction is to upwards, and z direction is out-of-the plane (towards you).

If the particle is moving with velocity $v_0$ in the presence of an external E-field, than according to the below formula E-field pushes the positive charge in the direction of the field, which is upward.

$F = Eq$ .

If the velocity of the particle is unchanged, this means that the particle does not have an acceleration, so net force applied to the particle is zero.

We know that the force caused by the E-field is upwards, so an equal amount of another force is directed downwards. This second force is caused by magnetic field. $|F_B| = qvB$

$F_{net} = 0\\F_{net} = F_E - F_B\\0 = qE_0 - qvB\\qE_0 = qvB\\B = \frac{E_0}{v}$

This is the magnitude of the magnetic field.

For the direction of the magnetic field we can use right-hand rule with the following equation:

$F_B = q(v \times B)$

Here, $v$ is in the x-direction. $F_B$ is in the (-y)-direction.

According to the right-hand rule, B-field should be in the z-direction (out-of-the plane, towards you.)

Explanation:

3 0

3 years ago