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dimaraw [331]
3 years ago
11

Which ecosystem contains 32% of the world's producers

Physics
1 answer:
tangare [24]3 years ago
4 0
The Answer Is D 32 % Of The worlds production is In the marine ecosystem
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How do i do a Wavelength and frequency problem
KengaRu [80]

Answer:

wavelength = v/f or wavelength equals to velocity over frequency

frequency= v/w or velocity over wavelength

frequency= 1/p or one over period or time

7 0
4 years ago
A 1400-kg car is moving at a speed of 25m/s. how much kinetic energy does the car have?
Luba_88 [7]

Answer:

437.5Kjoules

Explanation:

K.E=half multiply by mass multiply by square of velocity

=437.5Kjoules

3 0
3 years ago
PLEASE HELP I'M LOST.
Zina [86]
A - 3
B - 1
C - 2
D - 4
E - 5
6 0
3 years ago
a heat engine with an efficiency of 30.0% performs 2500 j of work. how much heat is discharged to the lower temperature reservoi
Free_Kalibri [48]

Answer:

Q₂ = 5833.33 J

Explanation:

First we need to find the energy supplied to the heat engine. The formula for the efficiency of the heat engine is given as:

η = W/Q₁

where,

η = efficiency of engine = 30% = 0.3

W = Work done by engine = 2500 J

Q₁ = Heat supplied to the engine = ?

Therefore,

0.3 = 2500 J/Q₁

Q₁ = 2500 J/0.3

Q₁ = 8333.33 J

Now, we find the heat discharged to lower temperature reservoir by using the formula of work:

W = Q₁ - Q₂

Q₂ = Q₁ - W

where,

Q₂ = Heat discharged to the lower temperature reservoir = ?

Therefore,

Q₂ = 8333.33 J - 2500 J

<u>Q₂ = 5833.33 J</u>

7 0
3 years ago
A compact disc rotates at 500 rev/min. If the diameter of the disc is 120 mm, (a) What is the tangential speed of a point at the
svlad2 [7]

Answer:

(a) the tangential speed of a point at the edge is 3.14 m/s

(b) At a point halfway to the center of the disc, tangential speed is 1.571 m/s

Explanation:

Given;

angular speed of the disc, ω = 500 rev/min

diameter of the disc, 120 mm

radius of the disc, r = 60 mm = 0.06 m

(a) the tangential speed of a point at the edge is calculated as follows;

\omega = 500 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} = 52.37 \ rad/s

Tangential speed, v = ωr

                               v = 52.37 rad/s  x 0.06 m

                              v = 3.14 m/s

(b) at the edge of the disc, the distance of the point = radius of the disc

   at half-way to the center, the distance of the point = half the radius.

r₁ = ¹/₂r = 0.5 x 0.06 m = 0.03 m

The tangential velocity, v = ωr₁

                                       v = 52.37 rad/s x 0.03 m

                                       v = 1.571 m/s

5 0
3 years ago
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