Explanation:
The given data is as follows.
height (h) = 98.0 m, speed (v) = 73.0 m/s,
Formula of height in vertical direction is as follows.
h = 
,
or, t = 
Now, formula for the required distance (d) is as follows.
d = vt
= 
= 
= 326.5 m
Thus, we can conclude that 326.5 m is the horizontal distance from the target from where should the pilot release the canister.
Answer:
B) 8 T.
Explanation:
For an ideal gas , the gas law that it follow is as follows
P₁V₁ / T₁ = P₂ V₂ /T₂
This law is followed by all the gases whether mono atomic or diatomic.
In this case following information are given
P₂ / P₁ = 3
V₂ / V₁ = 3
T₁ = T
T₂ = ?
From the gas law formula given , we have
= 3 X 3 T
= 9 T
Change in temperature = 9T - T = 8 T.
The answer is 175184.08 joules
It is a seismograph that would be most useful.
On question 30, that is a displacement- time graph (DT). On this type of graph the gradient is equal to the velocity. B has the steepest gradient, then A and finally C
Now velocity is a vector quantity so it has a direction and speed ( speed doesn't have a fixed direction.)
on the DT graph im going to assume that movement B is a positive velocity with A and C being negative.
So by ranking these: A is the most negative, C is the least negative and B has to be the greatest as it is the only positive velocity.
Q31, The same type of graph is present, by looking at the gradients we can rank the largest and smallest velocities- speeds in the case of the question.
i'll skip my working out as its the same as before:
C, B, A and then D
the same idea as on Q30 applies to Q31 part b,
D,C,B then A
