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tatyana61 [14]
3 years ago
7

To select the center of a line what option must be selected? A. Ortho B. Dynamic input C. Object snap

Engineering
1 answer:
Andru [333]3 years ago
5 0

Answer:

The correct answer is c. object snap  

Explanation:

In Autocad, the object snap is defined as a drawing aid that is used together with other different commands to help to draw accurately.  It also allows snapping onto a specific object location when there is a picking point. and thus, it helps to select the center of a line.

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The domain of discourse is the members of a chess club. The predicate B(x, y) means that person x has beaten person y at some po
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Answer:A. No one has ever beat Nancy.

Explanation:

The dormain of discourse in a simple language is the set of entities upon which our discussions are based when discussing about something.

The dormain of discourse is also known simply as universe, can also be said to be a set of entities o

upon which certain variables of interest in some formal treatment may range.

The dormain of discourse is generally attributed to Augustus De Morgan, it was also extensively used by George Boole in his Laws of Thought.

THE LOGICAL UNDERSTANDING OF THE THE QUESTION IS THAT NO ONE HAS EVER BEAT NANCY.

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3 years ago
Which of the following might be a job or task of an IT worker who manages
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Answer:

I'm pretty sure it's letter d

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3 years ago
If you replace the text value in an associative dimension, the text value will not change when the
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C

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What is the core domain for Accenture’s Multi-party Systems practice?
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digital identity is the answer

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3 years ago
The hot combustion gases of a furnace are separated from the ambient air and its surroundings, which are at 25 oC, by a brick wa
yanalaym [24]

Answer:

T1 = 625.54 K

Explanation:

We are given;

T_α = Tsur = 25°C = 298K

h = 20 W/m².K,

L = 0.15 m

K = 1.2 W/m.K

ε = 0.8

Ts = T2 = 100°C = 373K

T1 = ?

Assumption:

-Steady- state condition

-One- dimensional conduction

-No uniform heat generation

-Constant properties

From Energy balance equation;

E°in - E°out = 0

Thus,

q"cond – q"conv – q"rad = 0

K[(T1 - T2)/L] - h(Ts-T_α) - εσ (Ts⁴ – Tsur⁴)

Where σ is Stephan-Boltzmann constant and has a value of 5.67 x 10^(-8)

Thus;

K[(T1 - T2)/L] - h(Ts-T_α) - εσ (Ts⁴ – Tsur⁴) = 1.2[(T1 - 373)/0.15] - 20(373 - 298] - 0.8x5.67x10^(-8)[373⁴ - 298⁴] = 0

This gives;

(8T1 - 2984) - (1500) - 520.31 = 0

8T1 = 2984 + 1500 + 520.31

8T1 = 5004.31

T1 = 5004.31/8

T1 = 625.54 K

7 0
3 years ago
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