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ipn [44]
3 years ago
10

Explain why it is not advisable to wear Ornament like ring at work shop​

Engineering
1 answer:
disa [49]3 years ago
8 0

The reason that it is not advisable to wear Ornament like ring at work shop​ is that rings can be easily get caught and fingers or the hands of the person can be injured, cut, scared etc.

<h3>Why should you not wear a ring at work?</h3>

Jewelry is known to bring about a lot of safety hazards for people working around chemicals and others.

Note that the reason that it is not advisable to wear Ornament like ring at work shop​ is that rings can be easily get caught and fingers or the hands of the person can be injured, cut, scared etc.

Learn more about Ornament from

brainly.com/question/24286720

#SPJ1

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Technician A says that the connecting rod and main bearing caps should be marked before removing to ensure that they can be inst
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Answer:

Technician A

Explanation:

This is because when the dimacations are made, the surface area and length respectively can be maintained to reduce to idea of force which may lead to damage

3 0
2 years ago
An add tape of 101 ft is incorrectly recorded as 100 ft for a 200-ft distance. What is
baherus [9]

Answer:

the correct distance is 202 ft

Explanation:

The computation of the correct distance is shown below:

But before that correction to be applied should be determined

= (101 ft - 100 ft) ÷ (100 ft) × 200 ft

= 2 ft

Now the correct distance is

= 200 ft +  2 ft

= 202 ft

Hence, the correct distance is 202 ft

The same would be relevant and considered too

4 0
3 years ago
Water from a stationary nozzle impinges on a moving vane with turning angle θ = 120. The vane moves away from the nozzle with co
Tems11 [23]

Answer:

The force that must be applied to maintain the vane speed constant is 2771.26 N

Explanation:

Given;

turning angle of the vane = 120°

control volume velocity, u = 10 m/s

absolute velocity, v = 30 m/s

nozzle area = 0.004 m²

The force acting on the vane has horizontal and vertical components:

Based on Reynolds general control volume system;

The horizontal force component of the system, ∑Fₓ = ρW²A(1-cosθ)

where;

ρ is the density of water = 1000 kg/m³

W is the relative velocity = Absolute velocity - control volume velocity

W = v - u

    = 30 - 10 = 20m/s

∑Fₓ = ρW²A(1-cosθ) = 1000 x 20² x 0.004 (1 - cos 120) = 2400 N

The vertical force component of the system, ∑Fy = ρW²A(sinθ)

∑Fy = ρW²A(sinθ) = 1000 x 20² x 0.004 x sin(120) = 1385.6 N

The magnitude of the force applied = \sqrt{F_x^2 + F_y^2}

F = \sqrt{2400^2 + 1385.6^2} = 2771.26 \ N

The force that must be applied to maintain the vane speed constant is 2771.26 N

6 0
3 years ago
Read 2 more answers
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5 0
3 years ago
A manufacturing company has decided to be carbon free by 2030.
k0ka [10]

Answer:

company should focus on their goals

4 0
3 years ago
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