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3 years ago

How many mL of .1250 M KCl solution contains 2.330g of KCl? KCl = 74.55 amu

1 answer:

8 0

The amu is a unit which means the mass per neutron, So the 74.55 means the mass per mole KCl. So the mole number of 2.330g KCl is 2.330/74.55=0.031 mol. The volume is 0.031/0.1250=0.248 L ≈ 250 mL. So the answer is a.

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H 18 1.008 18 × 1.008 = 18.144

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===================

Total 294.307 g/mol

Answer: 294.307 g/mol

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