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kolbaska11
[484]
3 years ago
10
How many mL of .1250 M KCl solution contains 2.330g of KCl? KCl = 74.55 amu
Chemistry
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1
answer:
lozanna
[386]
3 years ago
8
0
The amu is a unit which means the mass per neutron, So the 74.55 means the mass per mole KCl. So the mole number of 2.330g KCl is 2.330/74.55=0.031 mol. The volume is 0.031/0.1250=0.248 L ≈ 250 mL. So the answer is a.
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