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irga5000 [103]
3 years ago
7

If Tony and Tanya both run at the same speed and in the same direction and they both run for the same amount of time, what can y

ou say about the distance they travel?
Physics
1 answer:
Marina86 [1]3 years ago
8 0

Answer: They travel equal distances

Explanation:

Distance is amount of space covered from one point to another. It is measured in metres. Distance = speed x time taken

In this case,

- Since Tony and Tanya both run at the same speed: let speed = b

- Also, both run for the same amount of time: let time = c

Therefore, distance covered by Tony and Tanya = speed x time taken

Distance = b x c

Distance = bc (i.e Tony travelled a distance of bc, so also Tanya)

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our friend is constructing a balancing display for an art project. She has one rock on the left (ms=2.25 kgms=2.25 kg) and three
Licemer1 [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The torque produced by the pile of rocks is \tau = 35.63\ N \cdot m  

b

The distance of the single for equilibrium to occur is r_s =1.62 \ m

Explanation:

From the question we are told that

     The mass of the left rock is  m_s = 2.25 \ kg

     The mass of the rock on the right m_p = 10.1 kg

    The distance from  fulcrum to the center of the pile of rocks is  r_p = 0.360 \ m

   

Generally the torque produced by the pile of rock is mathematically represented as

           \tau = m_p * g * r_p

Substituting values

         \tau = 10.1 * 9.8  * 0.360                  

          \tau = 35.63\ N \cdot m      

Generally we can mathematically evaluated the distance of the the single rock that would put the system in equilibrium as follows

   The torque due to the single rock is

           \tau = m_s  * g * r_s

At equilibrium the both torque are equal

            35.63 = m_s * r_s * g

Making r_s the subject of the formula

             r_s = \frac{35.63 }{m_s * g}

Substituting values

            r_s = \frac{35.63 }{2.25 * 9.8}

            r_s =1.62 \ m

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