..............no.......................
Answer:
32 m/s
Explanation:
The speed of a bus is 30 m/s due East wrt the passenger
He also sees a passenger on the bus walking to the back at 2 m/s.
We need to find the passenger's velocity relative to the bus. As the observer sees that the bus and the passenger are moving in opposite direction. Let v is the relative velocity. So,
v = 30 m/s + 2 m/s
v = 32 m/s
Hence, the passenger's velocity relative to the bus is 32 m/s.
The downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.
<h3>
Downward acceleration of the cylinder</h3>
The downward acceleration of the solid cylinder is determined from the principle of conservation of angular momentum as shown below;
Iα = Tr
where;
- I is moment of inertia of the solid cylinder
- α is angular acceleration of the cylinder
- T is tension in the string
- r is length of the string
α = Tr/I

where;
- a is the downward acceleration of the solid cylinder
- R is radius of the cylinder
Thus, the downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.
Learn more about acceleration here: brainly.com/question/605631
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Niels Bohr discovered of the nucleus and developed an atomic model
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