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3 years ago

Mechanical energy often changes between potential and kinetic energy. True or False

Physics

2 answers:

Allushta [10]3 years ago

8 0

I wanna say its ture but it didnt exactly say that is transfered from those types of energy so I would just say false

mr_godi [17]3 years ago

5 0

It is true that the Mechanical energy is often changes between potential and Kinetic energy.

Explanation:

Mechanical energy is the aggregate of potential energy and kinetic energy of an object. When the object is ''stationary'' or at ''rest'', potential energy will be maximum and kinetic energy will be zero.

When the object starts to move, potential energy decreases and kinetic energy increases from zero. As the distance moved by the object increases, potential energy reduces gradually.

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The mass of a moving object increases, but its speed stays the same. What happens to the kinetic energy of the object as a resul

ozzi

The correct answer is
B It increases.

In fact, the kinetic energy of a moving object is given by
$K= \frac{1}{2}mv^2$
where m is the mass of the object and v is its speed. We see that the kinetic energy is proportional to the mass and proportional to the square of the speed: in this problem, the speed of the object remains the same, while its mass increases, therefore the kinetic energy will increase as well.

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3 years ago

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The second-order rate constants for the reaction of oxygen atoms ·with aromatic hydrocarbons have been measured (R. Atkinson and

Blizzard [7]

Answer: Frequency factor A = 8 × 10⁹

activation energy Ea = 15.5 KJ/Mol

Explanation: to begin, let us first define the parameters given;

K₁ = 1.44 × 10⁷dm³mol⁻¹s⁻¹

K₂ = 3.03 × 10⁷ dm³mol⁻¹s⁻¹

K₃ = 6.9 × 10 dm³mol⁻¹s⁻¹

also T₁ = 300.3 K

T₂ = 341.2 K

T₃ = 392.2 K

we know that;

㏑ K₂ / K₁ = Ea/R [1/T₁ -1/T₂]

where R is given as 8.314 J/mol-k

Ea = activation energy

K₁, K₂ = rate constant

T₁, T₂ = Temperature

therefore, ㏑ (3.03 × 10⁷/ 1.44 × 10⁷) = Ea / 8.314 [1/300.3 - 1/341.2]

this gives Ea = 15496.16 J/Mol ≈ 15.5 KJ /Mol

∴ Ea = 15.5 KJ/ Mol

also given that K = A e⁻∧Ea/RT

here A = frequency factor

∴ 6.9 × 10⁷ = A e⁻ ∧(15496.16/8.314 × 392.2)

A = 7.99 × 10⁹ = 8 × 10⁹

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3 years ago

The pressure in a compressed air storage tank is 1200 kPa. What is the tank’s pressure in (a) kN and m units; (b) kg, m, and s u

elixir [45]

Explanation:

Given data

Pressure P=1200 kPa

To find

Pressure in

(a) kN/m²

(b) kg/m.s²

Solution

For Part (a)

$P=(1200kPa)(\frac{1kN/m^{2} }{1kPa} )\\P=1200kN/m^{2}$

For Part (b)

$P=(1200kPa)(\frac{1kN/m^{2} }{1kPa} )(\frac{1000kg.m/s^{2} }{1kN} )\\P=1,200,000kg/m.s^{2}$

For Part (c)

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3 years ago

You are determining the mass of an object using a triple beam balance. When the pointer is lined up with the zero mark, the ride

astra-53 [7]

We add the values on each of the riders:
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3 years ago

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A lever with an output arm of 0.8 meter has a mechanical advantage of 6. What is the length of the input

Novosadov [1.4K]

From the law of the lever:

mechanical advantage= input arm : output arm

input arm- a
output arm-b
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6=\frac{a}{0,8}\ \ |*0,8\\\\
6*0,8=a\\\\
a=4,8m

$
Input arm is equal 4,8m

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3 years ago