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Julli [10]
3 years ago
13

Three resistors connected in parallel have individual values of 4.0, 6.0, and 10.0 Ω, respectively. If this combination is conne

cted in series with a 12-V battery and a 2.0- Ω resistor, what is the current in the 10.0- Ω resistor?
Physics
1 answer:
vazorg [7]3 years ago
4 0

Answer:

The current in the 10.0- Ω resistor is 1.16A

Explanation:

When resistors are connected in series, they are have the same current.

When they are in parallel, their current is divided.

The equivalent resistance of parallel resistors R1 and R2 is:

Req = R1*R2/(R1 + R2)

Initially, we use Ohm's Rule to solve this question.

V = Ri

In which V is the Voltage, R is the resistence and i is the current.

Among two resistors, R1 and R2, in parralel, we have that

iR1 = i(0)R2/(R1 + R2)

In which i(0) is the current entering.

Three resistors connected in parallel have individual values of 4.0, 6.0, and 10.0 Ω, respectively. In series with a 12-V battery and a 2.0- Ω resistor.

The current entering the parallel is the same current as it is for the 2.0- Ω resistor, with 12 V.

It is

V = Ri

12 = 2i

i = 6A

This means that i(0) = 6A.

4.0, 6.0, and 10.0 Ω in parallel

We want the current in the 10.0 Ω resistor.

The current divisor is not applicable with 3 resistors. However, we can calculate the equivalent resistance for the resistors of 4 and 6, and then the current divisor with the 10. So

Req = 4*6/(4+6) = 2.4

iR10 = 6*2.4/(10 + 2.4) = 1.16

The current in the 10.0- Ω resistor is 1.16A

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xenn [34]

Answer:

A. It must be zero

Explanation:

A spacecraft leaves the solar system at a velocity of 1,500 m/s. The net force on this spacecraft is zero. What can we say about the spacecraft's acceleration?

According to Newton's second law

Force = Mass × acceleration

If the net force is zero

0 = mass × acceleration

0 = ma

a = 0/m

a = 0m/s²

this shows that the acceleration will be zero If the net force is zero

4 0
2 years ago
A car is traveling at the bottom of a 9.00-meter-radius circular hill with a constant speed v. The moment the car is at the bott
Rina8888 [55]

Answer:

Explanation:

reading of scale = reaction force of surface R

centripetal force = R - mg = m v² / R , m is mass , v is velocity and R is radius of the circular path .

R = mg + m v² / R

given ,

m v² / R = .80 mg

v² = .80 x g x R

= .8 x 9.8 x 9 = 70.56

v = 8.4 m /s

3 0
2 years ago
An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the
Lerok [7]
Answer:

Explanation:
Kinematics equation for first Object:

but:
The initial velocity is zero

it reach the water at in instant, t1, y(t)=0:


Kinematics equation for the second Object:
The initial velocity is zero

but:

it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s


The velocity is negative, because the object is thrown downwards
7 0
2 years ago
A boy is whirling a stone around his head by means of a string. The string makes one complete revolution every second, and the t
slega [8]

Answer:

The tension increases to four times its original value.

Explanation:

v = Velocity

r = Radius

m = Mass of stone

The centripetal force is

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The tension will balance the centripetal force

T=m\dfrac{v^2}{r}

\\\Rightarrow T\propto v^2

\dfrac{T_1}{T_2}=\dfrac{v_1^2}{v_2^2}\\\Rightarrow \dfrac{T_1}{T_2}=\dfrac{v_1}{2^2v_1^2}\\\Rightarrow \dfrac{T_1}{T_2}=\dfrac{1}{4}\\\Rightarrow T_2=4T_1

The new tension will be 4 times the old tension

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2 years ago
A falling raindrop accelerates from 15 m/s to 35 m/s in 2 seconds. What is the raindrop's acceleration?
Agata [3.3K]
Average acceleration is difference in velocity divided by time.
(35 - 15)/2 = 10 m/s² downward
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