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Mila [183]
2 years ago
13

PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!

Physics
1 answer:
Mama L [17]2 years ago
5 0

Answer:

the correct one is B     ₊₁e

Explanation:

In the radioactive emission process there are three fundamental types, enision of alpha particles, emission of beta rays and emission of high energy photons.

In beta particle emission processes, a neutron decomposes, emitting an electron and an antineutrino, so the mass number of the nucleus does not change, but the atomic number increases by one unit.

Another possibility is the emission of a positron (positive charge) plus a neutrino, in this case the atomic mass remains constant and the atomic number decreases by one unit.

The second beta emission process if it describes the situation presented, when reviewing the answers the correct one is B

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Is the amplitude just 2? Or do I combine all of them and do 6?​
oksian1 [2.3K]

Answer:

combine them all

6 m

Explanation:

7 0
2 years ago
A sensitive gravimeter at a mountain observatory finds that the free-fall acceleration is 0.0055 m/s2 less than that at sea leve
pshichka [43]
Gs*rs^2 = gm*rm^2 
<span>rm = rs*√gs/gm </span>
<span>rm = 6370*√9.83/(9.83-0.009) = 6372.92 </span>
<span>mountain observatory is placed at an altitude worth 2920 m asl

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
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7 0
3 years ago
lasie4. A 4 kg object is displaced to the right by a distance of 12 m underthe influence of the following forces: a 17 Nforce pu
Oksanka [162]

The work done by a constant force in a rectilinear motion is given by:

W=Fd\cos\theta

where F is the magnitude of the force, d is the distance and θ is the angle between the force and the displacement vector.

In this case we have two forces then we need to add the work done by each of them; for the first force we have a magnitude of 17 N, a displacement of 12 m and and angle of 0° (since both the displacement and the force point right); for the second force we have a magnitude of 36 N, a displacement of 12 m and an angle of 30°. Plugging these values we have that the total work is:

\begin{gathered} W=(17)(12)\cos0+(36)(12)\cos30 \\ W=578.123 \end{gathered}

Therefore, the total work done is 578.123 J and the answer is option E

6 0
10 months ago
A force of 45 N is applied tangentially to the rim of a solid disk of radius 0.12 m. The disk rotates about an axis through its
bearhunter [10]

Answer:

Mass of the disk will be 2.976 kg

Explanation:

We have given force F = 45 N

Radius of the disk r = 0.12 m

Angular acceleration \alpha =140rad/sec^2

We know that torque \tau =I\alpha

And \tau =Fr

So Fr=I\alpha , here I is moment of inertia

So 50\times 0.12=I\times 140

I=0.0428kgm^2

We know that moment of inertia I=\frac{1}{2}mr^2

So 0.0428=\frac{1}{2}\times m\times 0.12^2

m = 2.976 kg

6 0
3 years ago
Which one doesn't belong in the group? oxygen, sulfur, selenium,
vlada-n [284]
It’s gonna be Oxygen ....
3 0
2 years ago
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