That depends on the wavelength itself, like what type of wave it is and where on the spectrometer it is
Answer:
a) 12.8 N
b) 3.2 m/s²
Explanation:
I'm guessing the period is 0.5π s.
Period of a spring in simple harmonic motion is:
T = 2π √(m/k)
Given T = 0.5π and m = 2 kg:
0.5π = 2π √(2/k)
0.25 = √(2/k)
0.0625 = 2/k
k = 32
The spring constant is 32 N/m, and the maximum displacement is 0.4 m. The maximum force can be found with Hooke's law:
F = kx
F = (32 N/m) (0.4 m)
F = 12.8 N
The acceleration can be found with Newton's second law:
∑F = ma
kx = ma
(32 N/m) (0.2 m) = (2 kg) a
a = 3.2 m/s²
15/70 =3/14 miles per minute = 0.21 miles a minute. One mile in about 5 minutes. Sarah is shifting, I think (faster than me)
Answer:
0.25 cm³.
Explanation:
We shall apply Boyle's law to find the solution . According to it
PV = constant where P is pressure and V is volume of the gas.
P₁ V₁ = P₂V₂
1 x .5 = 2 x V₂
V₂ = 0.25 cm³.
The initial angular speed of the fan will be 55.0 rad/sec. The angular speed of the fan decreases to 84.7 rad/s in 2.96 s.
<h3>What is angular acceleration?</h3>
Angular acceleration is defined as the pace of change of angular velocity with reference to time.
Given data;
Final angular speed,
Initial angular speed, 
Time period,t= 2.96 s
Angular deceleration = 47.2 rad/s²
Hence the initial angular speed of the fan will be 55.0 rad/sec.
To know more about angular acceleration refer to the link ;
brainly.com/question/408236
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