At point x = 0, the particle accelerates. Since there will be change of velocity at that point. The the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.
Given that a 2.0 kg particle moving along the z-axis experiences the force shown in a given figure.
Force is the product of mass and acceleration. While acceleration is the rate of change of velocity. Both the force and acceleration are vector quantities. They have both magnitude and direction.
If the particle's velocity is 3.0 m/s at x = 0 m, that mean that the particle experience change of velocity at point x = 0. Since the the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.
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Answer:
4 m/s²
Explanation:
When the elevator is 1 m below point of contact , compression will be 1 m.
Restoring force in the spring will be 10600 N. Friction force of 17000N will also act in upward direction . The weight of 2000 x 9.8 N will act downwards
Force in down ward direction = 2000 x 9.8
= 19600 N
Force in upward direction
= 10600 + 17000
= 27600 N
Net force in upward direction
= 27600 - 19600
= 8000 N
Acceleration in upward direction
= 8000 / 2000
= 4 m/s²
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Answer:
The linear velocity of the object is 8.71 m/s.
Explanation:
Given;
mass of the object, m = 1 kg
radius of the circle, r = 3.3 meters
centripetal force, F = 23 N
Centripetal force is given by;

where;
v is the linear velocity of the object

Therefore, the linear velocity of the object is 8.71 m/s.
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