If the object is moving at a constant speed, acceleration is 0. So:

The resultant force is 0. So the force pushing the object must be equal to the friction force acting, so
Friction =
90 N
C) because a new substance is formed
B) not sure but might be because the chemical properties of the substance has changed
Answer:
b. varies inversely with the square of the distance from the center of Earth.
Explanation:
Comparing the Newton's law of universal gravitation and second law of motion;
from Newton's second law of motion,
F = ma ............. 1
from New ton's law of universal gravitation,
F =
........... 2
Equating 1 and 2, we have;
mg = 
g = 
Therefore, the acceleration due to gravity near Earth, g, is inversely proportional to the square of the distance from the center of Earth.
Answer:
280 N
Explanation:
Applying Newton's third second law of motion,
F = m(v-u)/t................... Equation 1
Where F = Magnitude of the average force on the ball during contact, v = final velocity of the ball, u = initial velocity of the ball, t = time of contact of the ball and the wall.
Note: Let the direction of the initial velocity of the ball be positive
Given: m = 4 kg, u = 3.0 m/s, v = -4.0 m/s (bounce off), t = 0.1 s
Substitute into equation 1
F = 4(-4-3)/0.1
F = 4(-7)/0.1
F = -28/0.1
F = -280 N.
Note: The negative sign tells that the force on the ball act in opposite direction to the initial motion of the ball
Answer:
68 °F, 293.15 K
Explanation:
Fahrenheit, Kelvin and Celsius are the different scales of temperature in which temperature is measured.
Given : T = 20°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
<u>T = (20 + 273.15) K = 293.15 K </u>
The conversion of T( °C) to T(F) is shown below:
T (°F) = (T (°C) × 9/5) + 32
So,
<u>T (°F) = (20 × 9/5) + 32 = 68 °F</u>