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adoni [48]
3 years ago
9

If you add a battery to a series circuit what will happen to the current in the circuit

Physics
1 answer:
Evgen [1.6K]3 years ago
4 0

If there wasn't any battery before, then there was no current
in the circuit before, and there IS one now.  That's just about
the greatest change possible.

If there WAS a battery there before and you added another one
in series with it, then there are a few different possibilities for the
effect on the current in the circuit:

-- If the new battery has the same voltage as the original one,
AND you connect the new one so that they're both in the same
direction, then the current in the circuit will become double the
original current (twice as much as it was before).

-- If the new battery has the same voltage as the original one, AND
you connect the new one so that they're in opposite directions, then
the two batteries cancel each other, the total voltage becomes zero,
and the current in the circuit completely disappears.

-- If the voltage of the two batteries is different AND you connect
the new one so that they're both in the same direction, then the
current in the circuit increases, by a factor of

         (sum of the two battery voltages)
divided by
         (voltage of the original battery alone).

-- If the voltage of the two batteries is different AND you
connect the new one so that they're in opposite directions,
then the current in the circuit decreases, by a factor of

           (difference of the two battery voltages)
divided by
            (voltage of the original battery alone)

and the current flows in the direction of whichever battery has
the greater voltage.  If the new battery has greater voltage than
the original one alone, then the current reverses, and flows in
the opposite direction.

I think that covers all the possibilities.
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An object has a mass of 50.0 g and a volume of 10.5 cm3. What is the object's density?
seraphim [82]
Volume=mass/density

volume=455.6/19.3

volume=23.6 mL

4 0
3 years ago
An object experiences an acceleration of -6.8 m/s​2.​ As a result, it accelerates from 54 m/s to a complete stop. How much dista
inessss [21]

Answer:

The distance traveled during its acceleration, d = 214.38 m

Explanation:

Given,

The object's acceleration, a = -6.8 m/s²

The initial speed of the object, u = 54 m/s

The final speed of the object, v = 0

The acceleration of the object is given by the formula,

                                      a = (v - u) / t   m/s²

       ∴                              t = (v - u) / a

                                         = (0 - 54) / (-6.8)

                                         = 7.94 s

The average velocity of the object,

                                       V = (54 + 0)/2

                                           = 27 m/s

The displacement of the object,

                                 d = V x t   meter

                                    = 27 x 7.94

                                    = 214.38 m

Hence, the distance the object traveled during that acceleration is, a = 214.38 m

3 0
3 years ago
The position of a particle as it moves along an y axis is given by y = (2.0cm)sin(πt/4), with t in second and y in centimeters.
irina [24]

Part a)

At t = 0  the position of the object is given as

x = 0

At t = 2

x = 2 sin(\pi/2) = 2cm

so displacement of the object is given as

d = 2 - 0 = 2cm

so average speed is given as

v_{avg} = \frac{2}{2} = 1 cm/s

Part b)

instantaneous speed is given by

v = \frac{dy}{dt}

v = 2cos(\pi t/4 ) * \frac{\pi}{4}

now at t= 0

v = \frac{\pi}{2} cm/s

at t = 1

v = 2 cos(\pi/4) * \frac{\pi}{4}

v = \frac{\pi}{2\sqrt2}

at t = 2

v = 0

Part c)

Average acceleration is given as

a_{avg} = \frac{v_f - v_i}{t}

a_{avg} = \frac{0 - \frac{\pi}{2}}{2}

a = -\frac{\pi}{4} cm/s^2

Part d)

Now for instantaneous acceleration

As we know that

a =- \omega^2 y

at t = 0

a = -\frac{\pi^2}{16} * 0 = 0 cm/s^2

at t = 1

y = \sqrt2 cm

now we have

a = -\frac{\pi^2}{16}*\sqrt2

At t = 2 we have

y = 2 cm

a = -\frac{\pi^2}{16}*2

a = -\frac{\pi^2}{8}

<em>so above is the instantaneous accelerations</em>

7 0
3 years ago
How much energy is transferred in 10 seconds with a current of 13 amperes and a potential difference of 230 volts?​
Serhud [2]

29900 J

Explanation:

Recall that

P = VI

= (230 volts)(13 A)

= 2990 watts

Also,

E = Pt

= (2990 watts)(10 s)

= 29900 J

5 0
2 years ago
What is the current in a circuit that has voltage of 121.3 V and a total resistance of 56.3
Anuta_ua [19.1K]

Answer:

2.15 ampere

Explanation:

I = V/ R

= 121.3/56.3

= 2.15 A

3 0
3 years ago
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