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3 years ago

When you are high up in the air you have greater potential energy less potential energy

Physics

1 answer:

mina [271]3 years ago

5 0

Answer:

Its Greater potential energy because the air is high up and that makes high energy power

Explanation:

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solids, liquids, and gases are three forms of matter that:a. take up space. b. have mass. c. are made of atoms. d. all of the ab

LiRa [457]

Answer:

Explanation:

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8 0

3 years ago

A child dangles a 1.50-kilogram stuffed toy 0.500 meters from the ground. What is the potential energy of the toy?

inn [45]

Since we know that
Gravitational potential energy = mass × height ×gravity

then

GPE = 1.5 kg x 0.500 m x 9.8m/s^2

therefore

GPE = 7.35 J

6 0

3 years ago

Read 2 more answers

A 11.0 kg test rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 1985 J by the time the rock

nirvana33 [79]

Answer:

h = 18.41 m

Explanation:

Given that,

Mass of a test rocket, m = 11 kg

Its fuel gives it a kinetic energy of 1985 J by the time the rocket engine burns all of the fuel.

According to the law of conservation of energy,

PE = KE = mgh

h is height will the rocket rise

$h=\dfrac{E}{mg}\\\\h=\dfrac{1985 }{11\times 9.8}\\\\h=18.41\ m$

So, the rocket will rise to a height of 18.41 m.

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3 years ago

The element carbon exists in several different forms. Pure carbon can be found in the form of diamonds, coal, and the graphite i

Artist 52 [7]

B is false.

not all carbon atoms have 6 neutrons. Carbon 13 for example has 7 neutrons

5 0

4 years ago

Read 2 more answers

Particle-X has a speed of 0.720 c and a momentum of 4.350x1019 kgm/s. What is the mass of the particle? 2.0206 10-27 kg Hints: T

kirill115 [55]

Explanation:

Given that,

Speed of particle = 0.720 c

Momentum = 4.350\times10^{-19}\ kgm/s[/tex]

(I). We need to calculate the mass of the particle

Using formula of momentum

$P=mv$

$m =\dfrac{P}{v}$

$m=\dfrac{4.350\times10^{-19}}{ 0.720\times3\times10^{8}}$

$m=2.013\times10^{-27}\ Kg$

We need to calculate the rest mass of particle

Using formula of rest mass

$m=\dfrac{m_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}$

Where, $m_{0}$ = rest mass

Put the value into the formula

$m_{0}=2.013\times10^{-27}\times\sqrt{1-(\dfrac{0.720 c}{c})^2}$

$m_{0}=2.013\times10^{-27}\times\sqrt{1-(0.720)^2}$

$m_{0}=1.4\times10^{-27}\ kg$

(b). We need to calculate the rest energy of the particle

Using formula of energy

$E_{0}=m_{0}c^2$

Put the value into the formula

$E_{0}=1.4\times10^{-27}\times(3\times10^{8})^2$

$E_{0}=1.26\times10^{-10}\ J$

(c). We need to calculate the kinetic energy of the particle

Using formula of kinetic energy

$K.E=mc^2-m_{0}c^2$

$K.E=(m-m_{0})\timesc^2$

$K.E=(2.013\times10^{-27}-1.4\times10^{-27})\times3\times10^{8}$

$K.E=1.84\times10^{-19}\ J$

(d). We need to calculate the total energy of the particle

Using formula of energy

$E=mc^2$

Put the value into the formula

$E=2.013\times10^{-27}\times(3\times10^{8})^2$

$E=1.812\times10^{-10}\ J$

Hence, This is the required solution.

8 0

3 years ago