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VladimirAG [237]
3 years ago
15

suppose that the earth were moved to a distance of 0.25 AU from the sun. How much stronger or weaker would the suns gravitationa

l pull on earth?explain​
Physics
1 answer:
Leviafan [203]3 years ago
3 0

Answer:

jnhvwlkj vkjsdjkf dskjlf

Explanation:

dfkj.kxc.lskfuf ibsf 89arfgs sv skdf afdvf zfdakm lfs buasrv, soci arsvibsk 9prguuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

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CAN SOMEONE PLEASE BE MY BOYFRIEND ANYONE JUST PLEASE ANSWER YES OR NO
Cerrena [4.2K]

Answer:

No

Explanation:

Because :)

5 0
4 years ago
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In 1958 a large earthquake in Alaska produced a tsunami. What was the approximate height of the tsunami?
lilavasa [31]
The approximate height of the tsunami in Alaska in 1958 is 1720ft
6 0
4 years ago
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a blackbody is radiating with a characteristic wavelength of 9 microns what is the blackbody temperature answer in kelvin
Daniel [21]

This question involves the concepts of Wein's displacement law and characteristic wavelength.

The blackbody temperature will be "3.22 x 10⁵ k".

<h3>WEIN'S DISPLACEMENT LAW</h3>

According to Wein's displacement law,

\lambda_{max} T = c\\\\T=\frac{c}{\lambda_{max}}

where,

  • \lambda_{max} = characteristic wavelength = 9 μm = 9 x 10⁻⁹ m
  • T = temperature = ?
  • c = Wein's displacment constant = 2.897 x 10⁻³ m.k

Therefore,

T=\frac{2.897\ x\ 10^{-3}\ m.k}{9\ x\ 10^{-9}\ m}

T = 3.22 x 10⁵ k

Learn more about characteristic wavelength here:

brainly.com/question/14650107

7 0
3 years ago
The law of universal gravitation states that any two objects in the universe that have mass without exception is called what
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Is it multiple choice?
7 0
4 years ago
Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla
juin [17]

To solve this problem we will apply the concept of Impulse. Which is described as the product between the Force and the change in time. Mathematically this can be described as

I = F \Delta t

Where,

F = Force

\Delta t= Time

Our values are given as,

F = 1450N

\Delta t = 5.1*10^{-3} s

Replacing we have,

I = (1450)(5.1*10^{-3})

I = 7.395Kg\cdot m/s

Therefore the impulse delivered to the soccer ball is 7.395Kg\cdot m/s or  7.395N\cdot s

4 0
3 years ago
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