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3 years ago

What symbol is used to show the standard reduction potential of an oxidation reaction in a half-cell?

1 answer:

6 0

The reduction potential of an oxidation reaction in a half-cell is denoted by the symbol E°.
Reduction potential is the tendency of a given chemical species to become reduced, that is, gain electrons or undergo a decrease in oxidation number. The greater the reduction potential, the more likely that a species will be reduced.

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Define saturated and unsaturated fats

saul85 [17]

Answer:

SATURATED: Saturated fat is a type of fat in which the fatty acid chains have all or predominantly single bonds.

UNSATURATED: Unsaturated fats are loosely packed. They tend to be liquid at room temperature.

There are two main types of unsaturated fat:

Monounsaturated

Polyunsaturated

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3 years ago

Solve the radical equation. what is the extraneous solution to the radical equation? the solution -1 is an extraneous solution.

Arada [10]

Answer:

X = 7

Explanation:

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2 years ago

Look at sample problem 19.10 in the 8th ed Silberberg book. Write the Ksp expression. Find the concentrations of the ions you ne

777dan777 [17]

Answer:

Explanation:

From the information given:

$CaF_2 \to Ca^{2+} + 2F^-$

$Ksp = 3.2 \times 10^{-11}$

no of moles of $Ca^{2+}$ = 0.01 L × 0.0010 mol/L

no of moles of $Ca^{2+}$ = $1 \times 10^{-5} \ mol$

no of moles of $F^-$ = 0.01 L × 0.00010 mol/L

no of moles of $F^-$ = $1 \times 10^{-6}\ mol$

Total volume = 0.02 L

$[Ca^{2+}}] = \dfrac{1\times10^{-5} \ mol}{0.02 \ L} \\ \\ \\ \[[Ca^{2+}}] = 0.0005 \ mol/L$

$[F^{-}] = \dfrac{(1\times 10^{-6} \ mol)}{0.02 \ L}$

$[F^{-}] = 5 \times 10^{-5} \ mol/L$

$Q = [Ca^{2+}][F^-]^2 \\ \\ Q = 0.0005 \times (5\times 10^{-5})^2 \\ \\ Q = 1.25 \times 10^{-12}$

Since Q<ksp, then there will no be any precipitation of CaF2

3 0

3 years ago

I need help with homework

Aliun [14]

Number 9 is A and 10 is A

5 0

3 years ago

You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain

Margarita [4]

Answer: 12

Explanation.

This problem was recently posted and deals with the conversion of units,so I give the same answer.

You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.

The conversion of units is easily undertaken once you build your conversion factors.

Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.

Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.

$a.1=a$

Then, build your conversion factor from the definitions given:

12 sleps is equal to 9 quibs.

12 sleps = 9 quibs

in virtue of the division property of equality, you can divide both sides by 12 sleps and get:

1 = 12 sleps / 9 quibs ← conversion factor

Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:

identity property: 9 quibs = 9 quibs × 1

substitution property: 9 quibs = 9 quibs × 12 sleps/ 9 quibs

You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.

So, all you have to do now is the operations with the numbers:

9 quibs = (9 × 12 / 9) sleps = 12 sleps ← answer

3 0

3 years ago