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3 years ago

How much force is needed to accelerate an object of mass 90 kg at a rate of 1.2 m/s2?

Physics

1 answer:

saw5 [17]3 years ago

7 0

It would be: F = m.a = 90 * 1.2 = 108 Kgm/s² = 108 N

So, force of 108 Newtons is required for that..

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A ball thrown with 50N of force accelerates at 25 m/s2. What is the mass of the ball?

MrRissso [65]

F=ma
Force is 50N. Acceleration is 25 m/s^2.
50N=m*25 m/s^2
Divide both sides by 25.
mass=2 kg

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3 years ago

What branch of science that deals with landforms,features,inhabitants and phenomena on earth

iren2701 [21]

Answer:

Earth and space

Explanation:

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3 years ago

Which could most likely describe the three surfaces?

sergiy2304 [10]

Answer:

Surface 1 is blacktop, Surface 2 is gravel, and Surface 3 is ice.

Explanation:

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3 years ago

Read 2 more answers

A uniformly charged rod (length = 2.0 m, charge per unit length = 3.0 nc/m) is bent to form a semicircle. What is the magnitude

Artist 52 [7]

Answer:

84.82N/C.

Explanation:

The x-components of the electric field cancel; therefore, we only care about the y-components.

The y-component of the differential electric field at the center is

$dE = \frac{kdQ }{R^2} sin(\theta )$ .

Now, let us call $\lambda$ the charge per unit length, then we know that

$dQ = \lambda Rd\theta$ ;

therefore,

$dE = \frac{k \lambda R d\theta }{R^2} sin(\theta )$

$dE = \frac{k \lambda d\theta }{R} sin(\theta )$

Integrating

$E = \frac{k \lambda }{R}\int_0^\pi sin(\theta )d\theta$

$E = \frac{k \lambda }{R}*[-cos(\pi )+cos(0) ]$

$E = \frac{2k \lambda }{R}.$

Now, we know that

$\lambda = 3.0*10^{-9}C/m,$

$k = 9*10^9kg\cdot m^3\cdot s^{-4}\cdot A^{-2},$

and the radius of the semicircle is

$\pi R = 2.0m,\\\\R = \dfrac{2.0m}{\pi };$

therefore,

$E = \frac{2(9*10^9) (3.0*10^{-9}) }{\dfrac{2.0}{\pi } }.$

$\boxed{E = 84.82N/C.}$

7 0

3 years ago

An acorn falls 10 meters in 4 seconds. What is its average velocity?

quester [9]

Answer:

Average velocity, V = 2.5m/s

Explanation:

Given the following data

Displacement = 10m

Time = 4secs

Average velocity can be defined as the rate of change in displacement with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, average velocity is given by the equation;

$Velocity = \frac{displacement}{time}$

$V = \frac{d}{t}$

Substituting into the above equation;

$V = \frac{10}{4}$

Average velocity, V = 2.5m/s

3 0

3 years ago