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agasfer [191]
3 years ago
14

A sample that cannot be seperated into 2 or more substances by physical means is

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
3 0
The answer is a pure substance.

Pure substance can also be divided into compounds or elements, they both cannot be separated by physical methods. And elements, cannot be further separated by chemical methods. Physical methods may include distillation, crystallization, evaporation etc.

Compunds are made up of 2 or more elements chemically combined together, though it can be separated using chemical methods such as heat or electricity.

But as these both compounds and elements cannot be separated by physical methods, they're called pure substance. Unlike mixtures, which can be separated using physical methods.
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A concentration cell consisting of two hydrogen electrodes (PH2 = 1 atm), where the cathode is a standard hydrogen electrode and
Lunna [17]

The pH of the unknown solution is 3.07.

<u>Explanation:</u>

<u>1.Find the cell potential as a function of pH</u>

From the Nernst Equation:

Ecell=E∘cell−RT /zF × lnQ

where

R denotes the Universal Gas Constant

T denotes the temperature

z denotes the moles of electrons transferred per mole of hydrogen

F denotes the Faraday constant

Q denotes the reaction quotient

Substitute the values,

E∘cell=0   lnQ=2.303logQ

E0cell=−2.30/RT /zF × log Q

Solving the equation,

<u>2. Find the Q  value</u>

Q=[H+]2prod pH₂, product/ [H+]2reactpH₂, reactant

Q=[H+]^2×1/1×1=[H+]2

Taking the log

logQ= log[H+]^2=2log[H+]=-2pH

From the formula,

Ecell=−2.303RT /zF× logQ

E cell= 2.303 × 8.314 CK mol (inverse)  × 298.15

K × 2pH /2×96 485  C⋅mol

( inverse)

E cell= 0.0592 V × pH

<u>3. Finding the pH value</u>

E cell= 0.0592 V × pH

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pH=3.07

The pH of the unknown solution is 3.07.

7 0
3 years ago
Draw a mechanism for the first step of the reaction between methyllithium (CH3Li) and acetone. Then answer the two multiple choi
pogonyaev

Answer:

See the attached image

Explanation:

The first step is the production of the <u>carboanion</u> in the CH_3Li compound. We will get the <u>negative charge</u> on the methyl group and the <u>positive charge</u> in the Li atom.

Then the carboanion can <u>attack the acetone</u>. The double bond of the oxo group would <u>delocalized</u> upon the oxygen, generating a positive charge in the carbon that can be attacked by the carboanion formaiting a <u>new C-C bond</u>.

8 0
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