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agasfer [191]
3 years ago
14

A sample that cannot be seperated into 2 or more substances by physical means is

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
3 0
The answer is a pure substance.

Pure substance can also be divided into compounds or elements, they both cannot be separated by physical methods. And elements, cannot be further separated by chemical methods. Physical methods may include distillation, crystallization, evaporation etc.

Compunds are made up of 2 or more elements chemically combined together, though it can be separated using chemical methods such as heat or electricity.

But as these both compounds and elements cannot be separated by physical methods, they're called pure substance. Unlike mixtures, which can be separated using physical methods.
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Zinc metal can be obtained from Zinc Oxide by reaction at high temperature with CO. The CO is obtained from burning C in limited
bonufazy [111]

Answer:

(a): 2ZnO(s) -----------> 2Zn(s) + O2(g)

2C(s) + O2(g) ---------> 2CO(g)

(b): ZnO(s) + C(s) ---------> Zn(s) + CO(g)

3 0
3 years ago
Could you please Calculate the number of atom of 40K (potassium 40) in 1gram of KCl. Taking into account the isotopic abundance
Crank

Answer:

9.53*10^{17} atoms of 40K

Explanation:

You can use the molecular mass and the Avogadro´s number, in the following formula:

N_{40K=\frac{m_{KCl}}{M_{MKCl}}}*N_{Avogadro}*(IA_{40k})

where m_{KCl} is the sample mass, M_{KCl} is the molecular mass of the KCl and IA(40K) is the isotopic abundance of 40K.

Now replacing the values, you can find:

N_{40K}=\frac{1g}{74.5513\frac{g}{mol}}*6.022*10^{23}mol^{-1} *0.000118

N_{40K}=9.53*10^{17} atoms

8 0
3 years ago
Which source of energy is a fossil fuel?
Ahat [919]
I'm only in middle school but i believe its coal.

8 0
4 years ago
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What is the length of one mole of the typical cell phone that is approximately 15 cm in length?
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The activation energy for a given reaction is 56 kj/mol. at what temperature would the rate constant be quadruple what is was at
Alex787 [66]

The rate equation is given as:

k = A e^(- Ea / RT)

 

Dividing state 1 and state 2:

k1/k2 = e^(- Ea / RT1) / e^(- Ea / RT2)

k1/k2 = e^[- Ea / RT1 - (- Ea / RT2)]

k1/k2 = e^[- Ea / RT1 + Ea / RT2)]

 

Taking the ln of both sides:

ln (k1/k2) = - Ea / RT1 + Ea / RT2

ln (k1/k2) = - Ea / R (1/T1 - 1/T2)

 

Since k2 = 4k1, therefore k1/k2 = ¼

 

ln (1/4) = [- (56,000 J/mol) / (8.314 J / mol K)] (1/273 K – 1/ T2)

2.058 x 10^-4 = 1/273 – 1/T2

T2 = 289.25 K

8 0
3 years ago
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