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patriot [66]
3 years ago
7

Two proteins associated with a rare neurodegenerative disorder have been sequenced. Protein A contains many polar amino acids wi

th small regions containing nonpolar, hydrophobic amino acids. Protein B is rich in nonpolar, hydrophobic amino acids with only two small regions containing polar amino acids. What might this suggest about the two proteins? Two proteins associated with a rare neurodegenerative disorder have been sequenced. Protein A contains many polar amino acids with small regions containing nonpolar, hydrophobic amino acids. Protein B is rich in nonpolar, hydrophobic amino acids with only two small regions containing polar amino acids. What might this suggest about the two proteins?
A. Protein A may be a cytoplasmic protein and Protein B may be a membrane associate protein.
B. The two proteins may have different secondary structures.
C. Protein A and Protein B are complementary parts of a supramolecular structure.
D. Protein A is fibrous and Protein B is globular.
E. Protein A is most likely and enzyme and Protein B is most likely a storage protein.
Biology
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

A. Protein A may be a cytoplasmic protein and Protein B may be a membrane associate protein.

Explanation:

According to the given information, protein A is rich in polar amino acids and consists of only a few nonpolar amino acids. This makes the protein A a cytoplasmic protein.

The cytoplasm consists of watery cytosol and the suspended organelles and other molecules. So, cytoplasmic proteins have a large number of polar amino acids so that they can adopt a stable conformation in the water-based surroundings.  

On the other hand, protein B is rich in nonpolar amino acids. Protein B might be a membrane protein. The core of the membrane is hydrophobic due to the presence of nonpolar tails of the phospholipid bilayers.

The proteins present in the membrane have nonpolar amino acids on their surfaces to make nonpolar interactions with the hydrophobic tails of the phospholipids.  

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Frequency of p = 0.684

Frequency of p = 0.316

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Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals (q^{2}) is \frac{10}{100} = 0.1

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