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Serhud [2]
3 years ago
11

I have a question regarding friction in rolling without slipping.

Physics
1 answer:
Solnce55 [7]3 years ago
4 0

Explanation:

They probably put "rolls without slipping" in there to indicate that there is no loss in friction; or that the friction is constant throughout the movement of the disk. So it's more of a contingency part of the explanation of the problem.

(Remember how earlier on in Physics lessons, we see "ignore friction" written into problems; it just removes the "What about [ ]?" question for anyone who might ask.)

In this case, you can't ignore friction because the disk wouldn't roll without it.

As far as friction producing a torque... I would say that friction is a result of the torque in this case. And because the point of contact is, presumably, the ground, the friction is tangential to the disk. Meaning the friction is linear and has no angular component.

(You could probably argue that by Newton's 3rd Law there should be some opposing torque, but I think that's outside of the scope of this problem.)

Hopefully this helps clear up the misunderstanding for you.

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Arrange the following substances in order of decreasing magnitude of lattice energy.
kolbaska11 [484]
The formula is F = ( q1 * q2 ) / r ^ 2 
<span>where: q is the individual charges of each ion </span>
<span>r is the distance between the nuclei </span>
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A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume increases to 30.0 ml, at constant temperature is 0.25atm.

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According to Boyle's Law,

P₁V₁ = P₂V₂

where, P₁ is pressure exerted by the gas initially

V₁ is the volume of gas initially

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V₂ is the volume of gas finally

Given,

P₁ = 1.5 atm

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Learn more about Boyle's Law here, brainly.com/question/1437490

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