1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lozanna [386]
4 years ago
14

The first term of a geometric sequence is 7, and the ratio (multiplier) is 3. what is the sum of the first 5 terms of the sequen

ce? user: what is the 8th term of this geometric sequence? 6, 48, 384, 3072, . . .
Mathematics
1 answer:
Anni [7]4 years ago
4 0
Hello,

1)
a_{1}=7
a_{2}=7*3
a_{3}=7*3^2

a_{n}=7*3^{n-1}

s=a_{1}+a_{2}+a_{3}+a_{4}+a_{5}=7*(1+3^1+3^2+3^3+3^4)
=7*\frac{3^{5}-1}{3-1}
=7*242/2=847

2)
b_{8}=6*8^{8-1}=12582912




















You might be interested in
Rosa's dog had three puppies. After a few months, she measured the weight of the four dogs. The weights were 16 pounds, 18.5 pou
Free_Kalibri [48]

Answer:

Part A: The outlier is the 60 lbs dogs, because this dog disrupts the common pattern amongst the others, therefore it is an outlier.

Part B: The mean of all 4 dogs is is 28.5, and the mean of the 3 dogs without an outlier is 13.5. This means the difference is 15, hence 28.5-13.5=15

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
the length of a model car is 1/20 of the length of the actual car. If the model is 8.7 in. long, how long is the actual car?
frez [133]
1/20 is equl to 5% so... 8.7 / 5% =?  or    8.7 / 0.05 = ?

the answer is............ 174 in.
3 0
4 years ago
Find x so that QS ‖ PT. PQ = 15, QR = 3, RS = 8, ST = x – 3
zzz [600]

Answer:

x=12

Step-by-step explanation:

oPQ= 15 and ST= x-3 and segment PQ and segment ST are congrunt so 15-3=12 and that makes x 12

6 0
3 years ago
Thomas hiked 6 miles on Monday 10 miles on Tuesday and 8 miles on Wednesday which value is closest to the mean number of miles h
german

Answer:

8 miles

Step-by-step explanation:

6 + 10 + 8 = 24

24/3 = 8

7 0
4 years ago
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
4 years ago
Other questions:
  • Can someone double check this please
    14·1 answer
  • How much is it 2 5/6-1/8<br> Explain:
    13·1 answer
  • Can you plz help me with these 4-9
    12·1 answer
  • LOOK AT THE BOTTOM MAKE SURE YOU ARE RIGHT ?????????????????????????????/
    5·2 answers
  • What is sin 0 when cot 0 = {?
    10·2 answers
  • If car cover 400km/in 8hr what is the distance cover in 15 hr​
    10·1 answer
  • 230 is equal to _____. <br> A. 0<br> B. 1/23<br> C. 1<br> D. 23
    8·1 answer
  • According to her running log, Ariana averaged 4 miles per week last month and 75% less this month. How much did she average this
    15·1 answer
  • 4. IN YOUR OWN WORDS How can you find the area of a composite figure?
    8·1 answer
  • What is the domain of f(x)?<br> O{x-4 O x1-3 O {x|1 O {x| 2 &lt; x ≤ 4}
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!