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Sergeeva-Olga [200]

2 years ago

13

A small child watches as you stir a spoonful of sugar into your kool aid the child says she believes that the sugar went away be

cause it seemed to disappear. How could you explain to the child what happened to the sugar and how could you show her you can get it back

1 answer:

viktelen [127]2 years ago

6 0

The sugar dissolved in the kool aid, <span>become or cause to become incorporated into a liquid so as to form a solution. the proof that the sugar is present because it made the kool aid taste sweeter which is a property of the sugar. to get back the sugar we must heat the kool aid until sugar residue will remain</span>

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What is the molality of a solution in which 0.42 moles aluminum chloride has been dissolved in 4200 water ?

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Answer:

0.1 M

<h3>Explanation:</h3>

Molarity refers to the concentration of a solution in moles per liter.
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2 years ago

Which of the following possess the greatest concentration of hydroxide ions?

jek_recluse [69]

Answer : The correct option is (d) a solution of 0.10 M NaOH

Explanation :

<u>(a) a solution of pH 3.0</u>

First we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-3.0=11$

Now we have to calculate the $OH^-$ concentration.

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$11=-\log [OH^-]$

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<u>(b) a solution of 0.10 M $NH_3$ </u>

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We have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$12=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-12}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-12}M$

<u>(d) a solution of 0.10 M NaOH</u>

As we know that $NaOH$ is a strong base. So, it dissociates to give $Na^+$ ion and $OH^-$ ion.

So, 0.10 M of $NaOH$ in a solution dissociates to give 0.10 M of $Na^+$ ion and 0.10 M of $OH^-$ ion.

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As we know that 1 mole of $HNO_2$ in a solution dissociates to give 1 mole of $H^+$ ion and 1 mole of $NO_2^-$ ion.

So, $1\times 10^{-4}M$ of $HNO_2$ in a solution dissociates to give $1\times 10^{-4}M$ of $H^+$ ion and $1\times 10^{-4}M$ of $NO_2^-$ ion.

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