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Artemon [7]
3 years ago
12

Application of using in chemistry ?please answer me​

Chemistry
2 answers:
emmainna [20.7K]3 years ago
8 0

The Scope of Chemistry in Industry

The Scope of Chemistry in IndustryChemistry plays an important and useful role towards the development and growth of a number of industries. This includes industries like glass, cement, paper, textile, leather, dye etc. We also see huge applications of chemistry in industries like paints, pigments, petroleum, sugar, plastics, Pharmaceuticals.

The Scope of Chemistry in IndustryChemistry plays an important and useful role towards the development and growth of a number of industries. This includes industries like glass, cement, paper, textile, leather, dye etc. We also see huge applications of chemistry in industries like paints, pigments, petroleum, sugar, plastics, Pharmaceuticals.It has also helped in the greater production of sulphuric acid, nitric acid, and Ammonia, hydrogenated oils by providing suitable catalysts.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

djverab [1.8K]3 years ago
4 0

Answer:

Applications of Chemistry:

Chemistry plays an important and useful role towards the development and growth of a number of industries. This includes industries like glass, cement, paper, textile, leather, dye etc. We also see huge applications of chemistry in industries like paints, pigments, petroleum, sugar, plastics, Pharmaceuticals.

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6.47 M (3 s.f.)

Explanation:

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3 years ago
What is the density of a 6 g of pure copper with a volume of 12 mL?
Sati [7]

Answer:

The density of copper is 0.5 g/mL

Explanation:

Given data:

Mass of copper = 6 g

Volume of copper = 12 mL

Density of copper = ?

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d = m/v

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3 years ago
At 506 K and 2.05 atm, if 6.00 grams of H2 will reacts with excess N2 what volume in liters will be produced of NH3? (R = 0.0820
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Answer:

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Explanation:

You must convert the 6.00 grams of H₂ into number of moles, and then use the stoichiometry of the reaction to find the number of moles of NH₃, which can be converted into volume using the ideal gas equation.

<u></u>

<u>1. Number of moles of H</u><u>₂</u>

  • number of moles = mass in grams / molar mass
  • molar mass of H₂ = 2.016g/mol
  • number of moles = 6.00grams / 2.016g/mol = 2.97619mol

<u></u>

<u>2. Number of moles of NH</u><u>₃</u>

<u></u>

i) Chemical equation:

  • 3H₂(g) + N₂(g) →  2NH₃(g)

ii) Mole ratio:

  • 3 mol H₂ : 2 mol NH₃

iii) Proportion:

  • x mol  NH₃ / 2.97619mol H₂ = 3 mol NH₃ / 2 mol H₂

  • x = 4.4642857mol NH₃

<u>3. Volume of NH₃</u>

  • pV = nRT
  • V = nRT/p
  • V = 4.4642857mol × 0.08206 atm·liter/(K·mol) × 506K / 2.05atm
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