Question

A uniform rod rotates in a horizontal plane about a

Answer 1

Answer

given,

length of rod (L)= 6 m

weight of the rod (W)= 10 N

rotates at = 240 rev/min

                = $240\times \dfrac{2\pi}{60}$

                = 25.13 rad/s

a)  Rotational inertia of the rod about axis of rotation

$I = I_{CM} + m d^2$

d is the distance from the center of gravity.

  d = L/2

$I = \dfrac{1}{2}mL^2+ m (\dfrac{L}{2})^2$

$I = \dfrac{3}{4}mL^2$

$I = \dfrac{3}{4}\times \dfrac{10}{9.8}\times 6^2$

  I = 27.55 kg.m²

rotational moment of inertia of the rod is equal to I = 27.55 kg.m²

b)angular momentum of rod

   L = I ω

   L =27.55 x 25.13

   L = 692.36 Kg.m²/s

angular momentum of rod is equal to L = 692.36 Kg.m²/s