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3 years ago

A uniform rod rotates in a horizontal plane about a

Physics

1 answer:

Dmitrij [34]3 years ago

3 0

Answer

given,

length of rod (L)= 6 m

weight of the rod (W)= 10 N

rotates at = 240 rev/min

= $240\times \dfrac{2\pi}{60}$

= 25.13 rad/s

a) Rotational inertia of the rod about axis of rotation

$I = I_{CM} + m d^2$

d is the distance from the center of gravity.

d = L/2

$I = \dfrac{1}{2}mL^2+ m (\dfrac{L}{2})^2$

$I = \dfrac{3}{4}mL^2$

$I = \dfrac{3}{4}\times \dfrac{10}{9.8}\times 6^2$

I = 27.55 kg.m²

rotational moment of inertia of the rod is equal to I = 27.55 kg.m²

b)angular momentum of rod

L = I ω

L =27.55 x 25.13

L = 692.36 Kg.m²/s

angular momentum of rod is equal to L = 692.36 Kg.m²/s

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To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.

The electric field is

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Here,

$\lambda$ = Linear charge density

$\epsilon_0$ = Permittivity of free space

r = Distance

The linear charge density can be written as,

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$\lambda = \frac{q}{L}$

Replacing,

$E = \frac{\frac{q}{L}}{2\pi \epsilon_0 r}$

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The initial and final electric Force can be written as function of the charge and the electric field as

$F_i = E_i q$

$F_f = E_f q$

If we replace the value for the electric field we have,

$F_i = (\frac{q}{2\pi \epsilon_0 rL})q = (\frac{q^2}{2\pi \epsilon_0 rL})$

Length is one third at the end, then

$F_f = (\frac{q}{2\pi \epsilon_0 r(L/3)})q = (\frac{3q^2}{2\pi \epsilon_0 rL})$

The ratio of the force is

$\frac{F_f}{F_i} = \frac{(\frac{3q^2}{2\pi \epsilon_0 rL})}{(\frac{q^2}{2\pi \epsilon_0 rL})}$

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Answer: Visual acuity: sharpness of vision.

Myopia: nearsightedness

Refraction: bending of light rays.

Emmetropia: normal vision.

Accommodation: changes the shape of the eye lens to focus light on the retina.

Presbyopia: age-related farsightedness due to loss of elasticity in the lens.

Astigmatism: reduction in visual acuity due to changes in the cornea or lens.

Hyperopia: farsightedness

Myopia and hyperopia are refractive errors of the eye.

Presbyopia occurs in old age people.

Explanation:

Visual acuity: It can be defined as the inability to observe the details of shape of the object. Person loses sharpness in vision.

Myopia: It is a defect in vision in which person is able to observe the near by objects clearly but not able to see the distant objects.

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Emmetropia: It is a vision without any defect.

Accommodation: It is the ability of the eye to adjust its focal length and adjusting the light on focus.

Presbyopia: It can be defined as the loss of ability of eye to focus on the object. It occurs in old age.

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harina [27]

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Answer:

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Explanation:

given:

L=8 cm

d_1=d_2=2.05_10^-3

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K_po=3

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required

U=??

solution:

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voltage is known but capacitance is not

we can consider the two plates of polystyrene and pyrex glass as a two separate capacitors connected on series so the total capacitance of series capacitor is given by:

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the capacitance of pyrex

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=128 pF

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substitution in 1 yields

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