1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lina20 [59]
4 years ago
9

Which force is the more dominant one in the hydrogen atom, the gravitational or the electrical? by what factor?

Physics
2 answers:
Arte-miy333 [17]4 years ago
7 0
The electrical is dominant.
In the hydrogen atom, the electrical force is vastly stronger than the gravitational. It is roughly 39 orders of magnitude greater, i.e. ratio of the electrical to gravitational force is on the order of 10^39.
marin [14]4 years ago
3 0

Answer:

Electrical Force by a factor of 2.23 \times 10^{39}

Explanation:

Known values

magnitude of the charge of an electron |e| = 1.6 \times 10^{-19}

magnitude of the charge of a proton |e| = 1.6 \times 10^{-19}

Note: magnitude means we only consider positive numerical value

mass of an electron m = 9.1  \times 10^{-31} kg

mass of an electron M = 1.7 \times 10^{-27} kg

Electric force,F_e = \frac{ke^{2}}{r^{2}}

Gravitational force,F_g = \frac{GMm}{r^{2} }

\frac{Electric force }{Gravitational force}  = \frac{\frac{ke^{2}}{r^{2}}}{ \frac{GMm}{r^{2} }} \\\\\frac{Electric force }{Gravitational force}  = \frac{ke^2}{GMm} \\\\\frac{Electric force }{Gravitational force}  = \frac{9 \times 10^9 \times (1.6 \times 10^{-19})^2}{6.67 \times 10^{-11} \times 1.7 \times 10^{-27} \times 9.1 \times 10^{-31}} \\\\\frac{Electric force }{Gravitational force}  = 2.23 \times 10^{39}

You might be interested in
A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest and is pulled up a mine s
Ierofanga [76]

Answer:

a). P=11.04kW

b). Pmax=11.38 kW

c). Wt=6423.166kJ

Explanation:

The power of the motor when the speed is constant is the work in a determinate time.

P=\frac{W}{t}

The work is the force the is applicated in a distance so

W=F*d

replacing:

P=F*\frac{d}{t} and \frac{d}{t} determinate distance in time is velocity so

a).

P=F*v

F=m*a\\F=m*g*sin(33.5)

P=950kg*9.8\frac{m}{s^{2}}*sin(33.5)*2.15\frac{m}{s}\\P=11047.846 W\\P=11.0478 kW

b).

The maximum power must the motor provide, is the maximum force with the maximum speed of the motor in this case

The first step is find the acceleration so

vi=0\frac{m}{s} \\vf=2.15 \frac{m}{s}\\vf=vi+a*t\\vf-vi=a*t\\ a=\frac{vf-vi}{t}= a=\frac{2.15\frac{m}{s}-0\frac{m}{s}}{13s}\\a=0.1653 \frac{m}{s^{2}}

The maximum force is when the car is accelerating so

Ft=Fa+Fg\\Ft=m*a+m*g*sin(33.5)\\Ft=950kg*0.1653\frac{m}{s^{2}}+950*9.8\frac{m}{s^{2}}*sin(33.5)\\Ft=5295.565 N

so the maximum force is the maximum force by the maximum speed

Pmax=Ft*v\\Pmax=5295.565N*2.15\frac{m}{s}\\Pmax=11385.46\\Pmax=11.3854kW

c).

The total energy transfer without any friction is the weight move in the high axis y in this case, so is easy to know that distance

W=m*g*h

h=Length*sin(33.5)

W=m*g*Length*sin(33.5)

W=950 kg*9.8* 1250m*sin(33.5)

W=6423166.667 kJ

W=6423.166 kJ

4 0
4 years ago
How much time does it take to use 300 W of power to do 1800 J of work? Round your answer to the nearest whole number. The time i
patriot [66]
Energy = power × time
1800 = 300 × time
time = 1800 ÷ 300 = 6 s

Hope it helped!
4 0
3 years ago
Read 2 more answers
A car is traveling at a speed of 50 m/sec when it suddenly accelerates at a rate of 5 m/sec2. How fast will the car be going (fi
NISA [10]

Answer:

200 ms-1

Explanation:

v = u+ at

v = 50+ 5×30

v = 200 ms-1

5 0
3 years ago
A 5.00 kg pendulum swings back and forth. At the top of its arc, it reaches a height of 0.36 m. What is the velocity of the pend
ella [17]
Tools we'll use:

--     Gravitational potential energy = (mass) x (gravity) x (height)

--     Kinetic energy (of a moving object) = (1/2) (mass) x (speed)²

When the pendulum is at the top of its swing,
its potential energy is

                             (mass) x (gravity) x (height)

                         =  (5 kg) x (9.8 m/s²) x (0.36 m)

                         =      (5 x 9.8 x 0.36)        joules

                         =            17.64 joules .

Energy is conserved ... it doesn't appear or disappear ...
so that number is exactly the kinetic energy the pendulum
has at the bottom of the swing, only now, it's kinetic energy:

                   17.64 joules  =  (1/2) x (mass) x (speed)²

                   17.64 joules  =  (1/2) x (5 kg) x (speed)²

Divide each side by 2.5 kg:

                   17.64 joules / 2.5 kg  =  speed²

Write out the units of joules:

                   17.64 kg-m²/s²  /  2.5 kg  =  speed²

                   (17.64 / 2.5) (m²/s²)  =  speed²

                       7.056 m²/s²  =  speed²

Take the square root
of each side:              Speed = √(7.056 m²/s²)

                                           =    2.656 m/s .

Looking through the choices, we're overjoyed to see
that one if them is  ' 2.7 m/s '.  Surely that's IT !
_______________________________

Note:
The question asked for the pendulum's 'velocity', but our (my) calculation
only yielded the speed.

In order to describe a velocity, the direction of the motion must be known,
and the question doesn't give any information on exactly how the pendulum
is hanging, and how it's swinging. 

We know that at the bottom of its swing, the motion is completely horizontal,
but we have no clue as to what direction.  So all we can discuss is its speed.
6 0
3 years ago
A flywheel in a motor is spinning at 530 rpm when a power failure suddenly occurs. The flywheel has mass 40.0kg and diameter 75.
aleksley [76]

Answer:

 w = 25.05 rad / s ,     α = 0.7807 rad / s² ,   θ = 1972.75

Explanation:

This is a kinematic rotation exercise, let's start by looking for the acceleration when the engine is off

            θ = w₀ t - ½ α t²

            α = (w₀t - θ) 2/t²

           

let's reduce the magnitudes to the SI system

 

w₀ = 530 rev / min (2pi rad / 1 rev) (1 min / 60 s) = 55.5 rad / s

θ = 250 rev (2pi rad / 1 rev) = 1570.8 rad

 

let's calculate the angular acceleration

           α = (55.5 39 - 1570.8) 2/39²

           α = 0.7807 rad / s²

having the acceleration we can calculate the final speed

           w = w₀ - ∝ t

           w = 55.5 - 0.7807 39

           w = 25.05 rad / s

the time to stop w = 0

           0 = wo - alpha t

           t = wo / alpha

           t = 55.5 / 0.7807

           t = 71.09 s

         

the angle traveled

       w² = w₀⁹ - 2 α θ

       w = 0

      θ = w₀² / 2α

let's calculate

      θ = 55.5 2 / (2 0.7807)

        θ = 1972.75

5 0
3 years ago
Other questions:
  • __________ is not included in your perception time.
    11·2 answers
  • A galvanic (voltaic) cell consists of an electrode composed of manganese in a 1.0 M manganese(II) ion solution and a second elec
    14·1 answer
  • An analogy makes a comparison between objects based on their similar qualities. Cassidy wanted to create an analogy for the moti
    14·2 answers
  • Learning Goal:
    15·1 answer
  • If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t2. (a) What
    5·1 answer
  • g Two cars, car 1 and car 2 are traveling in opposite directions, car 1 with a magnitude of velocity v1=13.0 m/s and car 2 v2= 7
    5·1 answer
  • What are the units of mass and weight
    14·2 answers
  • Where is the potential energy of a magnet stored?
    9·1 answer
  • Join my Kahoo t<br> pin-04454287<br><br> join if u like anime
    5·2 answers
  • How can people help stop erosion on beach
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!