Insulation or insulating. :) Hope that helps!
Larger tug force = 2*cos20 forward + 2*sin20 to the right (starboard)
<span>Smaller tug force = 1*cos15 forward + 1*sin15 to the left (port) </span>
<span>Resultant force forward = 2*cos20 + 1*cos15 = 2.8453 (4dp) </span>
<span>Resultant force to right = 2*sin20 - 1*sin15 = 0.4252 (4dp) </span>
<span>Angle of resultant force = arctan(0.4252 / 2.8453) = arctan(0.1494) = 8.5 degrees</span>
Your answer is infrared, visible, ultraviolet.
Answer:
One way to look at this is to consider the forces acting on any point in a string.
For a very small portion of string F = M a must still hold. As M approaches zero the small portion of string would have to approach infinite acceleration if the net force on that portion of string were not zero.
One generally considers the net force acting on the center of mass of an object not the individual forces acting on each infinitesimal mass composing
the object.
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