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Tamiku [17]
2 years ago
7

How many joules of work are done against a truck when a force of 50 N pushes it 1 kilometer away

Physics
1 answer:
ELEN [110]2 years ago
8 0

Answer:

Work = 50,000 J

Explanation:

Work = force * distance

Given that,

  • force = 50N
  • Distance = 1km = 1000m

Work = 50 * 1000

Work = 50,000 J

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Answer:

224 N

Explanation:

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How does a compound differ from a mixture?
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A compound is the substances that are formed by combining two are more chemical elements. A mixture is a substance created from two or more matter that can be separate with the help of physical methods. ... Mainly pure water is part of the compound. Mixtures fall under impure water.

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3 years ago
Read 2 more answers
A rocket travels at a speed of 14,000 m/s. What is the distance travelled by the rocket in 150s?
kati45 [8]

1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):

v=\frac{S}{t}

Rearranging the equation, we can write

S=vt

In this problem, v=14000 m/s and t=150 s, so the distance travelled by the rocket is

S=vt=(14000 m/s)(150 s)=2.1 \cdot 10^6 m


2) We can solve the second part of the problem by using the same formula we used previously. This time, t=300 s, so we have:

S=vt=(14000 m/s)(300 s)=4.2 \cdot 10^6 m/s

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3 years ago
How is work related to potential energy and kinetic energy?
NemiM [27]
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Work is the force on the object as it changes a distance. Interestingly, as work is done on an object, potential energy can be stored in that object. For example, if you carry a load up the stairs. Now that load will have potential energy that can be transformed into kinetic energy and so on
3 0
2 years ago
Denial cycled at 6 mph for 0.8 h. Then he jogged at 2 mph for
dexar [7]
<h3>Deniel's average speed for the total</h3><h3>distance is 3.6 mph</h3>

Average speed is difined as the total distance travelled divided by the total time required to cover the distance. Mathematically, it is expressed as:

Ave. Speed = \frac{Total distance }{Total time}

To obtain the average speed of Daniel, we shall determine the distance travelled in each case. This is illustrated below:

<h3>Case 1:</h3>

Speed 1 (S₁) = 6 mph

Time 1 (t₁) = 0.8 h.

<h3>Distance 1 (D₁) =? </h3>

Speed = \frac{Distance}{Time} \\\\S_{1}  = \frac{D_{1}}{t_{1}} \\\\6 = \frac{D_{1}}{0.8}

Cross multiply

D₁ = 6 × 0.8

<h3>D₁ = 4.8 mile</h3>

<h3>Case 2:</h3>

Speed 2 (S₂) = 2 mph

Time 2 (t₂) = 1.2 h.

<h3>Distance 2 (D₂) =? </h3>

S_{2} = \frac{D_{2}}{t_{2}}\\\\2 = \frac{D_{2}}{1.2}

Cross multiply

D₂ = 2 × 1.2

<h3>D₂ = 2.4 mile </h3>

Next, we shall determine the total time. This can be obtained as follow:

Time 1 (t₁) = 0.8 h.

Time 2 (t₂) = 1.2 h.

<h3>Total time (T) =? </h3>

T = t₁ + t₂

T = 0.8 + 1.2

<h3>T = 2 h</h3>

Next, we shall determine the total distance. This can be obtained as follow:

Distance 1 (D₁) = 4.8 mile

Distance 2 (D₂) = 2.4 mile

<h3>Total distance (D) =?</h3>

D = D₁ + D₂

D = 4.8 + 2.4

<h3>D = 7.2 mile</h3>

Finally, we shall determine the average speed of Daniel. This can be obtained as follow:

Total time = 2 h

Total distance  = 7.2 mile

<h3>Average speed =?</h3>

Ave. speed = \frac{Total distance }{Total time} \\\\Ave. speed = \frac{7.2 }{2}

<h3>Average speed = 3.6 mph</h3><h3 />

Therefore, the average speed of Daniel is 3.6 mph

Learn more: brainly.com/question/680492

5 0
2 years ago
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