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Gnom [1K]
3 years ago
7

Which of the following materials is necessary to stop a beta particle

Chemistry
1 answer:
stich3 [128]3 years ago
5 0
The material needed to stop a beta particle is c. thin pieces of wood.
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PLEASEEEEEEEEEEEE HELPPPPPPPP I BEGGGGG FOR HELPPPPP
Elza [17]

Answer: There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{63.00g}{18g/mol}=3.5moles

1 mole of H_2O contains =  6.023\times 10^{23} molecules

Thus 3.5 moles of H_2O contains =  \frac{6.023\times 10^{23}}{1}\times 3.5=21.08\times 10^{23} molecules.

There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

3 0
3 years ago
Which type of worm has a body that is divided into many ring-like parts?
yan [13]
Annelid im pretty sure
8 0
3 years ago
The power has gone out and you find a flashlight that uses batteries. When you turn on the flashlight, you are transforming:
Semenov [28]
In a flashlight, the electrical energy becomes light energy and thermal energy in the bulb.
5 0
3 years ago
Read 2 more answers
What are some synonyms for dissolved
Luba_88 [7]
*Go into solution
*Break down
*Liquefy
*Disintegrate
*Melt away
*Evaporate
*Dissapear

Hope it helps! Brainliest answer, PLZ? :)
4 0
3 years ago
The rate constant for this second‑order reaction is 0.380 M − 1 ⋅ s − 1 0.380 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
Sati [7]

Answer: 8.38 seconds

Explanation:

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

a_0 = initial concentartion = 0.860 M

a= concentration left after time t = 0.230 M

k = rate constant =0.380M^{-1}s^{-1}

\frac{1}{0.860}=0.380\times t+\frac{1}{0.230 }

t=8.38s

Thus it will take 8.38 seconds for the concentration of  A to decrease from 0.860 M to 0.230 M .

5 0
3 years ago
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