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3 years ago

A runner completes a 400-meter race in 2.5 mins. What is the runner's average speed?

Chemistry

1 answer:

NNADVOKAT [17]3 years ago

8 0

The average speed is 160 meters a minute.

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On the periodic table, calcium and bromine are located in period 4. What is one difference between the two elements?

Dovator [93]

Answer:

Explanation:

Just look at the groups and their tendencies. Or look at their electron configurations. You will notice that calcium has 2 valence electrons and bromine has 7 valence electrons.

Halogens have the most valence electrons possible without completing a shell (8 would be needed for that)

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3 years ago

Which system sends messages to organs and tissues? excretory muscular nervous circulatory

vampirchik [111]

Answer:

Hi friend, the answer to your question is NERVOUS SYSTEM.

Explanation:

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3 years ago

Which items are properties of acids? soapy sour bitter sharp possible burns

Burka [1]

Sour sharp and possible burns

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3 years ago

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What is the number assigned to an element on the Periodic Table?

spayn [35]

Answer:

Element Atomic Number One number you will find on all periodic tables is the atomic number for each element.

Explanation:

hope it helps :))

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2 years ago

A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe

Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: $V_{1}$ = 571 mL, $T_{1} = 26^{o}C$

(a) $T_{2} = 5^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL$

(b) $T_{2} = 95^{o}F$

Convert degree Fahrenheit into degree Cesius as follows.

$(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL$

(c) $T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL$

8 0

3 years ago