Explanation:
According to the given data, we will calculate the following.
Half life of lipase = 8 min x 60 s/min
= 480 s
Rate constant for first order reaction is as follows.
=
Initial fat concentration = 45
= 45 mmol/L
Rate of hydrolysis = 0.07 mmol/L/s
Conversion X = 0.80
Final concentration (S) =
= 45 (1 - 0.80)
= 9
or, = 9 mmol/L
It is given that = 5mmol/L
Therefore, time taken will be calculated as follows.
t =
Now, putting the given values into the above formula as follows.
t =
=
=
= 27.38 min
Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.
The new pressure inside the syringe will be 1.25 atm
<h3>Gas law</h3>
At constant temperatures, the volume of a gas is inversely proportional to its pressure.
Thus: P1V1 = P2V2
In this case, P1 = 3.0 atm, V1 = 89.6 mL, V2 = 215 mL
P2 = P1V1/V2
= 3 x 89.6/215
= 1.25 atm
More on gas laws can be found here: brainly.com/question/1190311
Answer:
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Explanation:
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