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2 years ago

What do refrigerators and air conditioners use to move heat?

2 answers:

5 0

They use refrigerant, which freon is a type of. For the cooling mechanism of a refrigeration machine, a compressor pushes the liquid coolant out and into the expansion evaporator. The evaporator uses the cool temperature from the coolant and uses the forced air from a fan (example for AC or fridge) and into an expansion valve that regulates its flow to the next step. It then goes to a condenser where it goes back into a fluid from gas form and back to the compressor. I left a few steps out (it's been a while).

Aleksandr [31]2 years ago

3 0

your answer is Freon

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Compute the work performed when 32 pounds is lifted 10 feet.

Murljashka [212]

W = force * displacement
W = 32 pounds * 10 feet
Now you need to convert it to newton and meters
W = 142 N * 3.048 m = 434 J
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3 years ago

Explain why it took so long for psychology to be recognized and what things helped it to get recognized.

Juli2301 [7.4K]

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3 years ago

Given that water at standard pressure freezes at 0∘c, which corresponds to 32∘f, and that it boils at 100∘c, which corresponds t

Zolol [24]

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2 years ago

A. In one short sentence, explain why we call the force of gravity an attractive force.

kondor19780726 [428]

Answer:

Explanation:

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(b) Yes, it does and the formula for force of gravity between any two object is

F = G $\frac{m1m2}{r}$

where m1 and m2 are masses of the first and second object respectively

r is the distance between the center of the two masses

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2 years ago

Suppose that a nascar race car is moving to the right with a constant velocity of +86 m/s. What is the average acceleration of t

Stels [109]

(a) As the car is moving with constant velocity, it means the rate change of velocity does not change, therefore the average acceleration of the car is zero.

Thus, there is no acceleration, when velocity is constant.

(b) Average acceleration,

$a =\frac{ v-u}{\Delta t}$

Here, v is final velocity and u is the initial velocity and $\Delta t$ is the time interval.

As twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed, therefore

$a =\frac{ -86 \ m/s-86 \ m/s }{12 \ s} = - 14 .3 \ m/s^2$

Thus, the average acceleration of the car is $14 .3 \ m/s^2$ in the direction to the left.

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2 years ago