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grigory [225]
3 years ago
9

What ALWAYS occurs simultaneously with reduction?

Chemistry
2 answers:
Ksenya-84 [330]3 years ago
5 0

Answer:

Oxidation-reduction process or redox reaction are the reactions where oxidation and reduction processes happens simultaneously.

Lena [83]3 years ago
4 0

Answer:

Oxidation occurs simultaneously with reduction.

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Denumiți ionul produs în soluție atunci când de adaugă acizi în apa​
svet-max [94.6K]

Answer:

Ionul de hidroniu este un factor important atunci când avem de-a face cu reacții chimice care apar în soluții apoase. Concentrația sa în raport cu hidroxidul este o măsură directă a pH-ului unei soluții. Se poate forma atunci când un acid este prezent în apă sau pur și simplu în apă pură. Formula chimică este H3O +

Explanation:

The hydronium ion is an important factor when dealing with chemical reactions that occur in aqueous solutions. Its concentration relative to hydroxide is a direct measure of the pH of a solution. It can be formed when an acid is present in water or simply in pure water. It's chemical formula is H3O+

marke me as brainliest  please

3 0
3 years ago
Both pyrrole and pyridine are aromatic compounds, and undergo electrophilic aromatic substitution (EAS). Using a resonance argum
soldi70 [24.7K]

Answer:

See attached picture for both electrophillic substitution in pyrole and in pyridine.

Explanation:

5 0
4 years ago
Stoichiometric calculations are based on balanced chemical equations. the reason that chemical equations must always be balanced
Roman55 [17]
<span>Answer: Chemical equations are balanced in order to: 1) satisfy the Law of Conservation of Mass, and 2) establish the mole relationships needed for stoichiometric calculations. The Law of Conservation of Mass: The Law of Conservation of Mass states that mass cannot be created or destroyed.</span>
6 0
4 years ago
What is the molarity of a solution that is prepared by adding 3 moles of CaSO4 in 1.5 L of water?
blondinia [14]

Answer:

[CaSO_4] = 2 mol/L

Explanation:

[CaSO_4] = \frac{3 mol}{1.5 L} = 2 mol/L

6 0
2 years ago
Which of the following answers below is the correctly balanced half-reaction for the reduction of the SO4 ^-2 ion in acid soluti
Rom4ik [11]

Answer:

C

Explanation:

The oxidation number of Sulphur in SO4^2- is;

x + 4(-2) = -2

x - 8 = -2

x = -2 + 8

x = 6

Now,

the oxidation number of sulphur in H2SO3 is

2 (1) + x + 3(-2) = 0

2 + x -6 = 0

-4 + x = 0

x = 4

Hence, the oxidation number of sulphur changed from +6 to +4 which signifies  gain of two electrons as shown in option C.

8 0
3 years ago
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