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Lera25 [3.4K]
2 years ago
13

What is the volume in liters of 5.25 moles of He gas?​

Chemistry
1 answer:
serious [3.7K]2 years ago
5 0

Answer:

\boxed {\boxed {\sf 117.6 \ L \ He}}

Explanation:

Regardless of the type of gas, 1 mole at standard temperature and pressure (STP) occupies a volume of 22.4 liters. In this case the gas is helium (He).

We can set up a ratio.

\frac { 22.4 \ L \ He}{ 1 \ mol \ He}

Multiply by the given number of moles.

5.25 \ mol \ He *\frac { 22.4 \ L \ He}{ 1 \ mol \ He}

The moles of helium will cancel.

5.25 *\frac { 22.4 \ L \ He}{ 1 }

5.25 * { 22.4 \ L \ He}

Multiply.

117.6 \ L \ He

5.25 moles of helium gas at STP is 117.6 liters of helium.

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Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

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Answer:

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Integration of the above linear equation =

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e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

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Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

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∴ the concentration at 10 minutes is ;

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