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2 years ago

14

Aluminum reacts with a certain nonmetallic element to form a compound with the general formula AlX. Element X is a diatomic gas

at room temperature. Element X must be __________. Group of answer choices oxygen fluorine chlorine nitrogen sulfur

1 answer:

Sergio039 [100]2 years ago

5 0

Answer:

It's nitrogen

Explanation:

cuz it has valence 3 and a diatomic gas at room temperature

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If a balloon containing 3000 L of gas at 39°C and 99 kPa rises to an altitude where the pressure is 45.5 kPa and the temperature

ludmilkaskok [199]

$\tt =3000~L\times \dfrac{289}{312}\times \dfrac{99}{45.5}$

<h3>Further explanation</h3>

Given

3000 L of gas at 39°C and 99 kPa to 45.5 kPa and 16°C,

Required

the new volume

Solution

Combined with Boyle's law and Gay Lussac's law

$\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}$

T₁ = 39 + 273 = 312

T₂ = 16 + 273 = 289

Input the value :

V₂ = (P₁V₁.T₂)/(P₂.T₁)

V₂ = (99 x 3000 x 289)/(45.5 x 312)

or we can write it as:

V₂ = 3000 L x (289/312) x (99/45.5)

3 0

2 years ago

A silver ring has a mass of 138.45 g. how many calories of heat are required to increase the temperature from 11.8 c to 162.5 c?

garik1379 [7]

A heat energy of 645

5 0

2 years ago

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Which two of the following elements would you expect to be most similar: nitrogen, chlorine, barium, fluorine, and sulfur?

Anon25 [30]

Nitrogen clorine flourine and sulfur

8 0

2 years ago

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How many mols of chlorine are in 120g of chlorine gas

xz_007 [3.2K]

Answer:

Number of moles of chlorine = 3.38 mol

Explanation:

Given data:

Mass of chlorine = 120 g

Moles of chlorine = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of chlorine = 35.5 g/mol

Now we will put the values in formula.

Number of moles = 120 g/ 35.5 g/mol

Number of moles = 3.38 mol

6 0

3 years ago

To interconvert the concentration units molality (m) and mass percent, you must also know the density of the solution. A) True B

uranmaximum [27]

Answer:

The correct answer is option false.

Explanation:

Molality of the solution defined as moles of substance present in 1 kilogram of solvent.

Moles = $\frac{Mass of solute}}{\text{molar mass of solute}}$

$Molality=\frac{Moles}{\text{Mass of solvent(kg)}}$

Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.

$(w/w\%)_=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.

Mass of solution = Mass of solute + Mass of solvent

7 0

3 years ago