
<h3>Further explanation</h3>
Given
3000 L of gas at 39°C and 99 kPa to 45.5 kPa and 16°C,
Required
the new volume
Solution
Combined with Boyle's law and Gay Lussac's law

T₁ = 39 + 273 = 312
T₂ = 16 + 273 = 289
Input the value :
V₂ = (P₁V₁.T₂)/(P₂.T₁)
V₂ = (99 x 3000 x 289)/(45.5 x 312)
or we can write it as:
V₂ = 3000 L x (289/312) x (99/45.5)
Answer:
Number of moles of chlorine = 3.38 mol
Explanation:
Given data:
Mass of chlorine = 120 g
Moles of chlorine = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of chlorine = 35.5 g/mol
Now we will put the values in formula.
Number of moles = 120 g/ 35.5 g/mol
Number of moles = 3.38 mol
Answer:
The correct answer is option false.
Explanation:
Molality of the solution defined as moles of substance present in 1 kilogram of solvent.
Moles = 

Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.

So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.
Mass of solution = Mass of solute + Mass of solvent