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lys-0071 [83]
3 years ago
13

Disulfide BondsA. Covalent interactions not found in all proteins.Peptide BondsB. Covalent interactions found in all proteins.Lo

ng-range interactionsC. Non-covalent interaction formed primarily on the interior of water-soluble proteins.Hydrophobic coreD. Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.
Chemistry
2 answers:
Fiesta28 [93]3 years ago
5 0

The complete question is: Match the following; Disulfide BondsA. Covalent interactions not found in all proteins.Peptide BondsB. Covalent interactions found in all proteins.Long-range interactionsC. Non-covalent interaction formed primarily on the interior of water-soluble proteins.Hydrophobic coreD. Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.

The answer

Disulfide Bonds (Covalent interactions not found in all proteins.)

Peptide Bonds (Covalent interactions found in all proteins.)

Long-range interactions (Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.)

Hydrophobic core. (Non-covalent interaction formed primarily on the interior of water-soluble proteins.)

Explanation:

The phrases have been given the right meaning enclosed in a parentheses. The should be matched accordingly as presented.

Sladkaya [172]3 years ago
4 0

Explanation:

A. Covalent interactions not found in all proteins - Disulfide Bonds

B. Covalent interactions found in all proteins - Peptide Bonds

C. Non-covalent interaction formed primarily on the interior of water-soluble proteins - Hydrophobic core

D. Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure - Long-range interactions.

Long-range interactions play an active role in the stability of protein molecules in terms of residue distances. disulfide bridges formed between thiol groups in two cysteine residues are an important component of the secondary and tertiary structure of proteins.

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Minerals are all naturally occurring solid substances with a definable chemical composition. They must also possess Group of ans
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They must also possess a fixed crystalline structure (spatial arrangement of atoms and ions).

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Calculate the sublimation pressure of the solid at the melting point of 400.00 K assuming that the enthalpy of sublimation is no
nasty-shy [4]

This question is incomplete, the complete question is;

Tonksite is a solid at 300.00K.  At 300.00 K its enthalpy of sublimation is 66.00 kJ/mol. The sublimation pressure at 300.00 K is 5.00 × 10⁻⁴ atm

Calculate the sublimation pressure of the solid at the melting point of 400.00 K assuming that the enthalpy of sublimation is not a function of temperature.

Answer: the sublimation pressure of the solid at the melting point is  0.3727 atm

Explanation:

Given that;

T1 = 300 K

T2 = 400 K

H_sub = 66 kJ/mol = 66000 J/mol

P1 = 5.00 × 10⁻⁴ atm

p2 = ?

now using the expression

log( p2 / 5.00 × 10⁻⁴ ) = (H_sub / R ×  2.303 ) (( T2 - T1) / T1T2)

now we substitute of given values into the expression

log(p2/p1) = (66000 / 8.314 ×  2.303 ) (( 400 - 300) / 300 × 400 )

p2 = 0.3727 atm

therefore the sublimation pressure of the solid at the melting point is  0.3727 atm

6 0
3 years ago
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