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Lana71 [14]
3 years ago
11

13) Calculate and Round to the correct number of significant digits. *

Chemistry
1 answer:
Lesechka [4]3 years ago
7 0

Answer:

333(3significants points)

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Assuming that sea water is a 3.5 wt % solution of NaCl in water, calculate its osmotic pressure at 20°C. The density of a 3.5% N
olga nikolaevna [1]

Answer:

π = 14.824 atm

Explanation:

wt % = ( w NaCL / w sea water ) * 100 = 3.5 %

assuming w sea water = 100 g = 0.1 Kg

⇒ w NaCl = 3.5 g

osmotic pressure ( π ):

  • π = C NaCl * R * T

∴ T = 20 °C  + 273 = 293 K

∴ C ≡ mol/L

∴ density sea water = 1.03 Kg/L....from literature

⇒ volume sea water = 0.1 Kg * ( L / 1.03 Kg ) = 0.097 L sln

⇒ mol NaCl = 3.5 g NaCL * ( mol NaCL / 58.44 g ) = 0.06 mol

⇒ C NaCl = 0.06 mol / 0.097 L = 0.617 M

⇒ π = 0.617 mol/L * 0.082 atm L / K mol * 293 K

⇒ π = 14.824 atm

7 0
4 years ago
How is 1 hectoliter different from 1 kiloliter?
LUCKY_DIMON [66]
1 hectoliter is 26.4172

1 kiloliter is 264.172
5 0
3 years ago
Read 2 more answers
If two separate containers A and B have the same volume and temperature, but container A has more gaseous molecules than B, then
topjm [15]

Answer:

Higher pressure, is the right answer.

Explanation:

The A will have a higher pressure. Since we have given the volume and temperature is same in both containers A and B. Below is the calculation for proof that shows which container has the higher pressure while keeping the volume and temperature the same.  

So, \ V_A = V_B \\\frac{n_A T_A}{P_A} = \frac{n_B T_B}{P_B} \\Here, \ T_A = T_B \\P_A = \frac{n_A}{n_B} \times P_B \\\frac{n_A}{n_B} > 1 \\\frac{P_A}{P_B} > 1 \\P_A > P_B \\

Therefore, the container “A” will have higher pressure.

8 0
3 years ago
Round 647.155 to nearest hundredt
lisov135 [29]

Answer:600

Explanation:

5 0
3 years ago
The gas in a closed container has a pressure of 3.00 x 10² kPa 30 ° C. What will the pressure be if the temperature is lowered t
Rainbow [258]

Answer: 100kPa

Explanation:

P1 = 3.00 x 10² kPa , P2 =?

T1 = 30°C = 30 +273 = 303k

T2 = —172°C = —172 + 273 = 101k

P1/T1 = P2/T2

3 x 10² / 303 = P2 / 101

P2 = (3 x 10² / 303) x 101

P2 = 100kPa

6 0
3 years ago
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