A diagram of a closed circuit with power source on the left labeled 30 V, a resistor on the top labeled 2 Ohms, a resistor on th
2 answers:
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Answer:
The magnification is -6.05.
Explanation:
Given that,
Focal length = 34 cm
Distance of the image =2.4 m = 240 cm
We need to calculate the distance of the object
Where, u = distance of the object
v = distance of the image
f = focal length
Put the value into the formula
The magnification is
Hence, The magnification is -6.05.