Answer:
a) -5.40 rad/s
b) -2.842 rad/s²
Explanation:
The direction is important in dealing with such questions. Clockwise is considered negative and counterclockwise is considered positive
a) Δω = final angular velocity - initial angular velocity
= -2.70 rad/s - 2.70 rad/s
= -5.40 rad/s
b) ∝ = Δω/Δt = (-5.40 rad/s)/1.90s = -2.842 rad/s²
Answer:
d = 8.4 cm
Explanation:
In order to calculate the amplitude of oscillation of the top of the building, you use the following formula for the max acceleration of as simple harmonic motion:
(1)
A: amplitude of the oscillation
w: angular speed of the oscillation = 2
f
f: frequency = 0.17Hz
The maximum acceleration of the top of the building is a 2.0% of the free-fall acceleration. Then, you have:

Then, you solve for A in the equation (1) and replace the values of the parameters:

The total distance, side to side, of the oscilation of the top of the building is twice the amplitude A. Then you obtain:
d = 2A = 2(4.2cm) = 8.4cm
"Energy and Momentum" is always conserved in an inelastic condition
Hope this helps!
Answer:

Explanation:
Energy is directly proportional to frequency and it is given as:
E = hf
where h = Planck's constant
f = frequency
To get frequency, we use the formula of speed:
c = λf
where c = speed of light
λ = wavelength
=> f = c/λ
Therefore, the energy of the photon will be:
E = hc/λ


The energy of the photon is 