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julia-pushkina [17]
2 years ago
15

A diagram of a closed circuit with power source on the left labeled 30 V, a resistor on the top labeled 2 Ohms, a resistor on th

e right labeled 3 Ohms and a resistor on the bottom labeled R Subscript 3 baseline.
If the current in this circuit is 3 A, what must be the value of R3?
Physics
2 answers:
sesenic [268]2 years ago
6 0

Answer:

5

Explanation:

larisa86 [58]2 years ago
3 0

Answer:

5

Explanation:

i dont have one

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A bicycle tire is spinning counterclockwise at 2.70 rad/s. During a time period At 1.90 s, the tire is stopped and spun in the o
Naddik [55]

Answer:

a) -5.40 rad/s

b) -2.842 rad/s²

Explanation:

The direction is important in dealing with such questions. Clockwise is considered negative and counterclockwise is considered positive

a) Δω = final angular velocity - initial angular velocity

          = -2.70 rad/s - 2.70 rad/s

          = -5.40 rad/s

b) ∝ = Δω/Δt = (-5.40 rad/s)/1.90s = -2.842 rad/s²

7 0
3 years ago
The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.17 Hz, and the acc
aksik [14]

Answer:

d = 8.4 cm

Explanation:

In order to calculate the amplitude of oscillation of the top of the building, you use the following formula for the max acceleration of as simple harmonic motion:

a_{max}=A\omega^2           (1)

A: amplitude of the oscillation

w: angular speed of the oscillation = 2\pif

f: frequency = 0.17Hz

The maximum acceleration of the top of the building is a 2.0% of the free-fall acceleration. Then, you have:

a_{max}=0.02(9.8m/s^2)=0.196\frac{m}{s^2}

Then, you solve for A in the equation (1) and replace the values of the parameters:

A=\frac{a_{max}}{\omega^2}=\frac{a_{max}}{4\p^2i f^2}\\\\A=\frac{0.196m/s^2}{16\pi^2(0.17Hz)^2}\\\\A=0.042m=4.2cm

The total distance, side to side, of the oscilation of the top of the building is twice the amplitude A. Then you obtain:

d = 2A = 2(4.2cm) = 8.4cm

4 0
3 years ago
What is conserved in an inelastic collision?
cupoosta [38]
"Energy and Momentum" is always conserved in an inelastic condition

Hope this helps!
4 0
3 years ago
A 5​-gram ​[g] rubber ball is released from a height of 8 meters​ [m] above a flat surface on the moon. Gravitational accelerati
Neko [114]

Answer:

v = 5.0911 m/s

Explanation:

See it in the pic.

6 0
3 years ago
Read 2 more answers
Green light can have a wavelength of 512 nm. The energy of a photon of this light is
Nat2105 [25]

Answer:

E = 3.88 * 10^{-17} J

Explanation:

Energy is directly proportional to frequency and it is given as:

E = hf

where h = Planck's constant

f = frequency

To get frequency, we use the formula of speed:

c = λf

where c = speed of light

λ = wavelength

=> f = c/λ

Therefore, the energy of the photon will be:

E = hc/λ

E = \frac{6.626 * 10^{-34} * 3 * 10^{8}  }{512 * 10^{-9} }

E = 3.88 * 10^{-17} J

The energy of the photon is 3.88 * 10^{-17} J

4 0
3 years ago
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