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3 years ago

Help please 80pnts and brainliest guaranteed

Physics

1 answer:

Ratling [72]3 years ago

8 0

Answer:

1. 1816

2. In order to make a weather map, what process was followed? They had to manually plot out the points of equal atmospheric pressure on an Isobar. Then, plot the rest of the information intended for that map.

3. Early weather maps could only be surface charts. There was no way of knowing what was happening higher in the troposphere so a complete picture of the atmosphere was impossible.

4. The weather maps are the most valuable tool to a meteorologist because it helps with the weather forecast. Without the weather maps it would be hard to predict what the weather would be. They help summarize what is going on in the atmosphere.

5. The information is then electronically sent to Washington, DC where it is analyzed.

Hope it helps! <3

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A 4.67-g bullet is moving horizontally with a velocity of +357 m/s, where the sign + indicates that it is moving to the right (s

Leni [432]

Answer:

(a)0.531m/s

(b)0.00169

Explanation:

We are given that

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Mass of block 2, $m_2=1626 g=1.626 kg$

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(a)

Let velocity of the second block after the bullet imbeds itself=v2

Using conservation of momentum

Initial momentum=Final momentum

$mv=m_1v_1+(m+m_2)v_2$

$4.67\times 10^{-3}\times 357+1.177(0)+1.626(0)=1.177\times 0.681+(4.67\times 10^{-3}+1.626)v_2$

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$1.66719-0.801537=1.63067v_2$

$0.865653=1.63067v_2$

$v_2=\frac{0.865653}{1.63067}$

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(b)Initial kinetic energy before collision

$K_i=\frac{1}{2}mv^2$

$k_i=\frac{1}{2}(4.67\times 10^{-3}\times (357)^2)$

$k_i=297.59 J$

Final kinetic energy after collision

$K_f=\frac{1}{2}m_1v^2_1+\frac{1}{2}(m+m_2)v^2_2$

$K_f=\frac{1}{2}(1.177)(0.681)^2+\frac{1}{2}(4.67\times 10^{-3}+1.626)(0.531)^2$

$K_f=0.5028 J$

Now, he ratio of the total kinetic energy after the collision to that before the collision

= $\frac{k_f}{k_i}=\frac{0.5028}{297.59}$

=0.00169

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