Question

A bungee jumper attains a speed of 30 m/s just as the bungee cord begins to stretch. If the period of stretch is 2 s while coming to a halt, the jumper's average deceleration in g’s is about ______?

Answer 1

Answer:

1.53 g

Explanation:

Given,

Initial speed = 30 m/s

Final speed = 0 m/s

Period of stretch, t = 2 s

average deceleration = ?

we know

$a = \dfrac{v-u}{t}$

$a = \dfrac{0-30}{2}$

a = -15 m/s²

Deceleration of the jumper = 15 m/s²

Deceleration in terms of g

$= \dfrac{15}{9.81}$

$= 1.53\ g$

Hence, the deceleration of the jumper is equal to 1.53 g