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andrew11 [14]
3 years ago
7

During sublimation the particles in a solid?

Physics
1 answer:
tigry1 [53]3 years ago
3 0

Answer: your mum likes it rough

Explanation:pp in bumhole=Baby

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A spring has a 12 cm length. When a 200-g mass is hung from the spring, it extends to 27 cm. The hanging mass were pulled downwa
BartSMP [9]

Answer:

The equation of the time-dependent function of the position is x(t)=5\cos(8.08t)

(b) is correct option.

Explanation:

Given that,

Length = 12 cm

Mass = 200 g

Extend distance = 27 cm

Distance = 5 cm

Phase angle =0°

We need to calculate the spring constant

Using formula of restoring force

F=kx

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{200\times10^{-3}\times9.8}{(27-12)\times10^{2}}

k=13.06\ N/m

We need to calculate the time period

Using formula of time period

T=2\pi\sqrt{\dfrac{m}{k}}

Put the value into the formula

T=2\pi\sqrt{\dfrac{0.2}{13.6}}

T=0.777\ sec

At t = 0, the maximum displacement was 5 cm

So, The equation of the time-dependent function of the position

x(t)=A\cos(\omega t)

Put the value into the formula

x(t)=5\cos(2\pi\times f\times t)

x(t)=5\cos(2\pi\times\dfrac{1}{T}\times t)

x(t)=5\cos(2\pi\times\dfrac{1}{0.777}\times t)

x(t)=5\cos(8.08t)

Hence, The equation of the time-dependent function of the position is x(t)=5\cos(8.08t)

8 0
3 years ago
How can damage to living things occur from exposure to X-rays or gamma
OLEGan [10]

Answer:C

Explanation:

just did the quiz

8 0
3 years ago
Read 2 more answers
A rod of 2.0-m length and a square (2.0 mm X 2.0 mm) cross section is made of a material with a resistivity of 6.0 E–8 Ohm meter
Alex Ar [27]

Answer:

8.33*10^-16 Watt

Explanation:

Given that

Length of the rod, l = 2 m,

Area of the rod, A = 2 x 2 mm² = 4*10^-6 m²

resistivity of the rod, p = 6*10^-8 ohm metre,

Potential difference of the rod, V = 0.5 V

Let R be the resistance of the rod, then

R = p * l / A

R = (6*10^-8 * 2) / (4*10^-6)

R = 3*10^14 ohm

Heat generated per second = V² / R Heat = (0.5)² / (3*10^14)

Heat = 0.25 / 3*10^14

Heat = 8.33*10^-16 Watt

Therefore, the rate at which heat is generated is 8.33*10^-16 Watt

4 0
4 years ago
ou are pushing a 20-kg box along a horizontal floor. Friction acts on the box. When you apply a horizontal force of magnitude 48
ziro4ka [17]

Answer:

The magnitude of the frictional force is 48.02 N

Explanation:

Mass of box = 20 kg

Weight of the box (Normal reaction) = mass × acceleration due to gravity = 20 ×9.8 = 196 N

Horizontal force applied = 48 N

Coefficient of friction = horizontal force ÷ normal reaction = 48 ÷ 196 = 0.245

Frictional force = coefficient of friction × normal reaction = 0.245 × 196 N = 48.02 N

5 0
3 years ago
Read 2 more answers
A dog walking to the right with a speed of 1.5 m s 1.5 s m ​ 1, point, 5, start fraction, start text, m, end text, divided by, s
harina [27]

Answer: 8.62

Explanation: it’s the answer. :)

4 0
3 years ago
Read 2 more answers
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