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GrogVix [38]
2 years ago
10

In the ground state of hydrogen, the uncertainty in the position of the electron is roughly 0.10 nm. If the speed of the electro

n is approximately the same as the uncertainty in its speed, about how fast is it moving
Physics
1 answer:
Kisachek [45]2 years ago
8 0

Answer:

\Delta v = 5.8 \times 10^5 m/s

Explanation:

given

uncertainly in the position of the electron  = 0.10 n m  (\Delta x)

using uncertainly principle

\Delta x .\Delta p = \frac{h}{4 \pi }

m\Delta v.\Delta x = \frac{h}{4 \pi }\\

after solving these equation we get

\Delta v = \frac{h}{4 \pi m\Delta x}

\Delta v = \frac{6.6\times 10^{34}} { 4 \times 3.14 \times 9.1\times 10^{-31} \times 0.10 \times 10^{-9}}

after solving we get

\Delta v = 5.8 \times 10^5 m/s

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