Answer:
Vapor pressure of solution = 23.9 Torr
Explanation:
Let's apply the colligative poperty of vapor pressure to solve this:
ΔP = P° . Xm
ΔP = Vapor pressure of pure solvent - Vapor pressure of solution
We have solvent and solute mass, so let's find out the moles of each.
55.3 g / 62 g/mol = 0.89 moles
285.2 g / 18 g/mol = 15.84 moles
Let's determine the mole fraction of ethylene glycol.
Mole fraction = Moles of ethylene glyco / Total moles
0.89 moles / (0.89 + 15.84) = 0.053
25.3 Torr - Vapor pressure of solution = 25.3 Torr . 0.053
Vapor pressure of solution = 25.3 Torr . 0.053 - 25.3 Torr
Vapor pressure of solution = 23.9 Torr
Answer:
Conservative Properties of Seawater
Explanation:
The Conservative properties of seawater refer to those properties that cannot be altered due to the occurrence of physical, chemical and biological processes, over the large oceanic bodies. This typically comprises properties such as the temperature and also there is a high concentration of both sodium and chloride ions, which increases the salinity of the oceans.
These conservative properties occur in almost a fixed amount, or it most probably changes at a very slower rate through time. They can be considered to have a long residence time.
Answer:
There will be 525.2 grams of K3N produced
Explanation:
Step 1: Data given
Number of moles of potassium oxide ( K2O) = 6 moles
Magnesium nitride (Mg3N) = in excess
Molar mass of K3N = 131.3 g/mol
Step 2: The balanced equation
Mg3N2 + 3K2O → 3MgO + 2K3N
Step 3: Calculate moles of K3N
The limiting reactant is K2O.
For 1 mol Mg3N2 consumed, we need 3 moles of K2O to produce 3 moles of MgO and 2 moles of K3N
For 6 moles K2O we'll have 2/3 * 6 = 4 moles of K3N
Step 4: Calculate mass of K3N
Mass of K3N = moles K3N * molar mass K3N
Mass of K3N = 4 moles * 131.3 g/mol
Mass of K3N = 525.2 grams
There will be 525.2 grams of K3N produced
