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3 years ago

5

my bf coming over after school and i still have no idea what to cook or make for him i can make almost everything but i have no

clue what tho can yall help me plzzzzzzzzzzzz give me ideas on what i should make

1 answer:

TiliK225 [7]3 years ago

4 0

Answer:

make cookies With him

Explanation:

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mr Goodwill [35]

The ball's vertical position $y$ in the air at time $t$ is

$y=v_0\sin31^\circ\,t-\dfrac g2t^2$

The ball is at its original height when $y=0$ , which happens at

$v_0\sin31^\circ\,t-\dfrac g2t^2=\dfrac t2\left(2v_0\sin31^\circ-gt)=0$

$\implies t=0\text{ and }t=\dfrac{2v_0\sin31^\circ}g$

Meanwhile, the ball's horizontal position $x$ at time $t$ is

$x=v_0\cos31^circ\,t$

So when the ball reaches its original height a second time, the ball will have traveled a horizontal distance of

$x=\dfrac{2{v_0}^2\sin31^\circ\cos31^\circ}g=\dfrac{{v_0}^2\sin(2\cdot31^\circ)}g$

(which you might recognize as the formula for the range of a projectile)

To reach a distance of $x=77\,\rm m$ , the initial speed $v_0$ would be

$77\,\mathrm m=\dfrac{{v_0}^2\sin62^\circ}{9.8\,\frac{\rm m}{\mathrm s^2}}\implies v_0=29\dfrac{\rm m}{\rm s}$

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3 years ago

Select all that apply. Sound is a ____ wave. longitudinal transverse pressure circular

elena-s [515]

The following apply:
Sound is a LONGITUDINAL wave.
Sound is a PRESSURE wave.
Longitudinal waves are waves in which the displacement of the medium is in the same direction as or opposite direction to the direction of wave propagation. An example of longitudinal wave is sound wave. Sound wave is also considered as a pressure wave as the result of the presence of repeating patterns of high and low pressure regions moving through a medium.

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4 years ago

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N in-ground swimming pool has the dimensions shown in the drawing. It is filled with water to a uniform depth of 3.00 m. The den

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Answer:

The pressure is $P = 1.31*10^{5} \ Pa$

Explanation:

From the question we are told that

The depth of the swimming pool is $d = 3.00 \ m$

The density of water is $\rho = 1.00*10^{3} \ kg /m^3$

Generally the total pressure exerted on the bottom of the swimming pool is mathematically represented as

$P = P_o + \rho * g * h$

Here $P_o$ is the atmospheric pressure with value

$P_o = 101325 \ Pa$

So

$P = 101325 + [1000 * 9.8 * 3]$

=> $P = 130725 \ Pa$

=> $P = 1.31*10^{5} \ Pa$

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It is in equilibrium if its velocity is not changing.

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A 540 g model rocket is on a cart that is rolling to the right at a speed of 2.5 m/s. The rocket engine, when it is fired, exert

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Answer:

horizontal distance left of the loop should you launch is 7.1m

Explanation:

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