A function must be one-to-one to and onto to have an inverse functionA. True B. False

Mathematics

1 answer:

kupik [55]3 years ago

3 0

Answer:

To have an inverse, a function must be injective i.e one-one and it must be surjective i.e. onto.

Since if it is not surjective, the function's inverse's domain will have some elements left out which are not mapped to any element in the range of the function's inverse.

So is it true.

Step-by-step explanation:

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Salem High School's winter sports teams WON 72% of their games last season. If the teams played 50 games, how many games did the

Dmitriy789 [7]

Answer

Find out the how many games did the teams lose .

To prove

Formula

$Percentage = \frac{Part\ value\times 100}{Total\ values}$

As given

Salem High School's winter sports teams WON 72% of their games last season.

If the teams played 50 games .

Percentage = 72%

Total value = 50

Put in the formula

$72 = \frac{Number\ of\ games\ win\times 100}{50}$

$Number\ of\ games\ win = \frac{72\times 50}{100}$

Number of games win = 36

Number of games teams loses = Total number of games - number of games win

= 50 - 36

= 14

Therefore the number of games team loses are 14 .

5 0

3 years ago

How do I solve this literal equation? <br> 15 points

kati45 [8]

Answer:

$\pi = \frac{A}{2r^2 + 2rh}$

Step-by-step explanation:

First, we need to isolate $\pi$ by taking it common from both terms on the right:

$A=2\pi r^2 + 2\pi rh\\A=\pi (2r^2 + 2rh)$

Now, since we want $\pi$ in terms of the other variables, we can divide the left hand side (A) by whatever is multiplied with $\pi$ on the right hand side. Then we will have an expression for $\pi$ . Shown below:

$A=\pi (2r^2 + 2rh)\\\pi = \frac{A}{2r^2 + 2rh}$