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eimsori [14]
3 years ago
13

How much time would it take for an object to fall 4.7 meters

Physics
1 answer:
levacccp [35]3 years ago
4 0

Answer:

4.7 is 10 as much as the number 0.47.

If you multiply 0.47 x 10 it will equal 4.7

Explanation:

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When throwing a ball upwards, the velocity is positive, and the acceleration is negative. True of False?
Setler79 [48]

Answer:

The velocity & acceleration will be taken as negative when a ball is thrown upward because work is done against the gravity.

Explanation:

3 0
3 years ago
If the new moon happens on January 15th, what shape will it be on February 6th?
Jobisdone [24]

-- From January 15 to February 6 is a period of 22 days.

-- The period of the full cycle of moon phases is 29.53 days.

-- So those dates represent (22/29.53) = 74.5% of a full cycle of phases.

-- That's almost exactly 3/4 of a full cycle, so on February 6, the moon would be almost exactly at <em>Third Quarter</em>.  That's the <em>left half of a disk </em>(viewed from the northern hemisphere).

3 0
3 years ago
A coil of 160 turns and area 0.20 m2 is placed with its axis parallel to a magnetic field of initial magnitude 0.40 T. The magne
ser-zykov [4K]

Answer:

The rate at which power is generated in the coil is 10.24 Watts

Explanation:

Given;

number of turns of the coil, N = 160

area of the coil, A = 0.2 m²

magnitude of the magnetic field, B = 0.4 T

time for field change = 2 s

resistance of the coil, R =  16 Ω

The induced emf in the coil is calculated as;

emf = dΦ/dt

where;

Φ is magnetic flux = BA

emf = N (BA/dt)

emf = 160 (0.4T x 0.2 m²)/dt

emf = 12.8 V/s

The rate power is generated in the coil is calculated as;

P = V²/ R

P = (12.8²) / 16

P = 10.24 Watts

Therefore, the rate at which power is generated in the coil is 10.24 Watts

8 0
3 years ago
A spring has a spring constant of 20 N/m. How much potential energy is stored in the spring as it stretched 0.20 m
makkiz [27]
The elastic potential energy (Ep) is given by Ep = \frac{1}{2}*k*x^2

Data: 
Ep = ? (Joule)
k = 20 N/m
x (displacement) = 0.20 m

Solving:
Ep = \frac{1}{2}*k*x^2
Ep = \frac{1}{2}*20*0.20^2
Ep =  \frac{20*0.04}{2}
Ep =  \frac{0.8}{2}
\boxed{\boxed{Ep = 0.4\:J}}\end{array}}\qquad\quad\checkmark
7 0
3 years ago
What is the minimum mass needed for a star to be on the main sequence? What happens to stars that do not meet the minimum mass?
Mariana [72]
Main sequence stars are characterised by the source of their energy.They are all undergoing fusion of hydrogen into helium within their cores. The mass of the star is the main element for such process or phenomenon to take place for it is a determinant of both the rate at which they perform the said activity and the amount of fuel available. 

To answer the question, the lower mass limit for a main sequence star is about 0.08. If the mass of a main sequence star is lower than the above-mentioned value, there would be a deficit or insufficiency of gravitational force to generate a standard temperature for hydrogen core fusion to take place and the underdeveloped star would form into a brown dwarf instead.
6 0
3 years ago
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