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2 years ago

Which of the following information is necessary to describe an object's motion?

Chemistry

2 answers:

Zepler [3.9K]2 years ago

8 0

Answer: The correct option is B.

Explanation: To describe the motion of an object, we use the equations of motion.

$v=u+at$
$s=ut+\frac{1}{2}at^2$
$2as=v^2-u^2$

From the above equations, we require position, speed and direction through which we an calculate the displacement, velocity and acceleration.

To calculate the complete motion of an object, we require all the three factors.

Hence, the correct option is B.

RSB [31]2 years ago

6 0

The answer is B) position,direction & speed hope i helped<span />

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A voltaic cell consists of a Zn>Zn2+ half-cell and a Ni>Ni2+ half-cell at 25 °C. The initial concentrations of Ni2+ and Zn

nlexa [21]

Answer :

(a) The initial cell potential is, 0.53 V

(b) The cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M is, 0.52 V

(c) The concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V are, 0.01 M and 1.59 M

Explanation :

The values of standard reduction electrode potential of the cell are:

$E^0_{[Ni^{2+}/Ni]}=-0.23V$

$E^0_{[Zn^{2+}/Zn]}=-0.76V$

From this we conclude that, the zinc (Zn) undergoes oxidation by loss of electrons and thus act as anode. Nickel (Ni) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) : $Zn\rightarrow Zn^{2+}+2e^-$ $E^0_{[Zn^{2+}/Zn]}=-0.76V$

Reaction at cathode (reduction) : $Ni^{2+}+2e^-\rightarrow Ni$ $E^0_{[Ni^{2+}/Ni]}=-0.23V$

The balanced cell reaction will be,

$Zn(s)+Ni^{2+}(aq)\rightarrow Zn^{2+}(aq)+Ni(s)$

First we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

$E^o=E^o_{[Ni^{2+}/Ni]}-E^o_{[Zn^{2+}/Zn]}$

$E^o=(-0.23V)-(-0.76V)=0.53V$

(a) Now we have to calculate the cell potential.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = emf of the cell = ?

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(0.100)}{(1.50)}$

$E_{cell}=0.49V$

(b) Now we have to calculate the cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M.

New concentration of $Ni^{2+}$ = 1.50 - x = 0.500

x = 1 M

New concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1 = 1.1 M

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(1.1)}{(0.500)}$

$E_{cell}=0.52V$

(c) Now we have to calculate the concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}+x]}{[Ni^{2+}-x]}$

Now put all the given values in the above equation, we get:

$0.45=0.53-\frac{0.0592}{2}\log \frac{(0.100+x)}{(1.50-x)}$

$x=1.49M$

The concentration of $Ni^{2+}$ = 1.50 - x = 1.50 - 1.49 = 0.01 M

The concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1.49 = 1.59 M

5 0

3 years ago

Which following substances is covalently bonded??

Stolb23 [73]

Where are the substances?

6 0

3 years ago

When the ph rises from 10 to 12 , how many more times has the solution become basic?

koban [17]

2 times

Hope this helps

3 0

2 years ago

For the reaction ? C6H6 + ? O2 → ? CO2 + ? H2O 42.5 grams of C6H6 are allowed to react with 113.1 grams of O2. How much CO2 will

ziro4ka [17]

Answer:

There will be 143,67g CO2 produced

Explanation:

2 C6H6 + 15 O2 → 12 CO2 + 6 H2O

(42,5 g C6H6) / (78.1124 g C6H6/mol) = 0.54408775 mole C6H6

(113.1 g O2) / (31.9989 g O2/mol) = 3.534496 moles O2

0.54408775 mole of C6H6 would react completely with 0.54408775 x (15/2) = 4.080658 mole O2, but there is more O2 present than that, so O2 is in excess and C6H6 is the limiting reactant.

(0.54408775 mol C6H6) x (12/2) x (44.0096 g/mol) = 143.67 g CO2

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3 years ago

PLZ HELP!!!! WILL MARK BRAINLYEST!!!!

Simora [160]

the answer is :

1)Earth’s position

3)tectonic activity

4)volcanic activity

5)solar energy

5 0

3 years ago

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