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Alex777 [14]
3 years ago
12

What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?

Chemistry
1 answer:
Julli [10]3 years ago
5 0

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

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The pipette that accurately measures 0.8mL of fluid is P1000 micropipette.

It is given that:-

The volume of fluid = 0.8mL

We know that,

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Hence,

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We know that, a P1000 micropipette's volume ranges between 200 microliter to 1000 micro liter.

As,

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The accuracy of this pipette decreases as volume decreases. Since the value 800 is near the maximum volume 1000 of the pipette, the accuracy of the pipette will be within a few percentages of the actual value.

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Molar mass H₂O = 18.0 g/mol

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molecules = 3.311x10²² / 1

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