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3 years ago

What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?

Chemistry

1 answer:

Julli [10]3 years ago

5 0

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

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3 years ago

What is the mass of 5.07 mol N2?<br><br> (Answer)grams (3 SF)

Nata [24]

Answer:

Mass, m = 141.96 kg

Explanation:

Given that,

Moles = 5.07

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We need to find the mass of 5.07 mol N₂.

We know that,

No of moles is equal to mass divided by molar mass i.e.

$n=\dfrac{m}{M}$

Where

m is mass of 5.07 mol of N₂

So,

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So, the required mass of 5.07 mol N₂ is 141.96 kg.

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