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Lubov Fominskaja [6]
3 years ago
11

Which of these electronic transitions in hydrogen is exothermic? question 11 options:

Physics
2 answers:
astra-53 [7]3 years ago
7 0

The electronic transition in a hydrogen atom from \boxed{{\text{a}}{\text{. n = 3 to n=2}}} is an exothermic process.

Further explanation:

An electronic transition is a process when an electron undergoes emission or absorption from one energy level to another energy level.

When an electron undergoes a transition from lower energy to the higher energy level then it requires energy to complete the process. Thus this transition is an absorption process.

When an electron undergoes a transition from higher energy to lower energy level then it emits the energy to complete the process. Thus this transition is an emission process.

The formula to calculate the difference between two energy levels of a hydrogen atom is,

 \Delta E={R_{\text{H}}}\left({\frac{1}{{{{\left({{{\text{n}}_{\text{i}}}}\right)}^2}}}-\frac{1}{{{{\left({{{\text{n}}_{\text{f}}}}\right)}^2}}}}\right)

Where,

\Delta E  is the energy difference between two energy levels.

{R_{\text{H}}}  is a Rydberg constant.

{{\text{n}}_{\text{i}}}  is the initial energy level of transition.

{{\text{n}}_{\text{f}}}  is the final energy level of transition.

The endothermic reactions are the reaction that absorbs heat from its surroundings. The exothermic reactions are reactions that release the heat to its surroundings.

Solution:

Classification of transitions

1. In the transition from n=1 to n=3, electron goes from lower energy level (n=1) to higher energy level (n=3). Therefore, it needs to absorb the energy. Hence, this transition is classified as an absorption process. Since absorption process required the energy to complete the process thus it is an endothermic process.

2. In transition from n=3 to n=2, electron goes from higher energy level (n=3) to lower energy level (n=2), therefore, it needs to emit the energy. Hence, this transition is classified as an emission process. Since emission process releases the energy to surrounding thus it is an exothermic process.

Learn more:

1. Identify oxidation numbers: <u>brainly.com/question/2086855 </u>

2. Calculation of volume of gas: <u>brainly.com/question/3636135 </u>

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: transition, a hydrogen atom, transition from n=1 to n=3, transition from n=3 to n=2, hydrogen, absorption process, emission process, endothermic and exothermic process.

Volgvan3 years ago
5 0
<span>The answer is Option a Reason The electron is moving closer to the nucleus. That is, in other words, it is moving to a lower energy level and will, therefore, give out energy When a transition gives out energy or in other terms it emits heat, it's exothermic. Hence the option a.</span>
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Answer:

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4 years ago
What are challenges of securing a crime scene
kotegsom [21]

At any crime scene, the two greatest challenges to the physical evidence are contamination and loss of continuity.

<h3>What is the meaning of physical evidence?</h3>

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7 0
2 years ago
A spaceship hovering over the surface of Venus drops an object from a height of 17 m. How much longer does it take to reach the
Paraphin [41]

1.96s and 1.86s. The time it takes to a spaceship hovering the surface of Venus to drop an object from a height of 17m is 1.96s, and the time it takes to the same spaceship hovering the surface of the Earth to drop and object from the same height is 1.86s.

In order to solve this problem, we are going to use the motion equation to calculate the time of flight of an object on Venus surface and the Earth. There is an equation of motion  that relates the height as follow:

h=v_{0} t+\frac{gt^{2}}{2}

The initial velocity of the object before the dropping is 0, so we can reduce the equation to:

h=\frac{gt^{2}}{2}

We know the height h of the spaceship hovering, and the gravity of Venus is g=8.87\frac{m}{s^{2}}. Substituting this values in the equation h=\frac{gt^{2}}{2}:

17m=\frac{8.87\frac{m}{s^{2} } t^{2}}{2}

To calculate the time it takes to an object to reach the surface of Venus dropped by a spaceship hovering from a height of 17m, we have to clear t from the equation above, resulting:

t=\sqrt{\frac{2(17m)}{8.87\frac{m}{s^{2} } }} =\sqrt{\frac{34m}{8.87\frac{m}{s^{2} } } }=1.96s

Similarly, to calculate the time it takes to an object to reach the surface of the Earth dropped by a spaceship hovering from a height of 17m, and the gravity of the Earth g=9.81\frac{m}{s^{2}}.

t=\sqrt{\frac{2(17m)}{9.81\frac{m}{s^{2} } }} =\sqrt{\frac{34m}{9.81\frac{m}{s^{2} } } }=1.86s

8 0
3 years ago
Read 2 more answers
Give me more thank plz​
spayn [35]
Ok bro you are going to have 1 more
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3 years ago
Why is it a good idea to extend your bare hand forward when you are getting ready to catch a fast-moving baseball?
qaws [65]

Answer:d

Explanation:

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While catching impulse is being transferred to hands imparting great force, lowering hand would increase the time so that average force decreases and chances to drop the ball also decreases.

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