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Arturiano [62]
3 years ago
7

Find the surface area 5 in 7 in 3 in​

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

Step-by-step explanation:

If theses are the edges of a prism then

Surface area = 2(5*7 + 5*3 + 7*3)

= 2 * 71

= 142 in^2.

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14 What are the solutions to the equation 3(x − 4)² = 27?
Marat540 [252]

Answer:

(1) 1 and 7

Step-by-step explanation:

Hello!

We can solve by isolating the variable.

<h3>Solve</h3>
  • 3(x - 4)² = 27
  • (x - 4)² = 9
  • √(x - 4)² = √9
  • (x - 4) = ± 3
  • x = 4 ± 3

There are two solutions, 1 and 7.

The answer is option 1: x = 7, x = 1.

4 0
2 years ago
If three pounds of coffee costs $22.56, what is the cost of 1
NeX [460]

Answer:

$7.52 = 7 dollars and 52 cents.

Step-by-step explanation:

Given that three pounds of coffee = $22.56

1 pound of coffee = $22.56/3

Thus, we would have:

\frac{22.56}{3} = 7.52.

A pound of coffee = $7.52

$7.52 = 7 dollars and 52 cents.

8 0
3 years ago
Find the slope of the line graphed below
taurus [48]
Hello,

A=(3,-4)
B=(-2,-1)

m=(-4+1)/(3+2)=-3/5
==============
3 0
3 years ago
Read 2 more answers
You are working as an office apprentice for the bksb Newcastle Arena.
Lemur [1.5K]

Answer:

18480\\ dollar

Step-by-step explanation:

1\\ Euro is equal to $1.54\\

The agreed fee is Euro 12000

Fees in dollars

= 12000 * 1.54\\= 18480\\ dollar

7 0
2 years ago
Read 2 more answers
3. A researcher randomly selects a sample of 61 former student leaders from a list of graduates of UNCG who had participated in
Sophie [7]

Answer:

not statistically significant at ∝ = 0.05

Step-by-step explanation:

Sample size( n )  = 61

Average for student leader graduates to finish degree ( x') = 4.97 years

std = 1.23

Average for student body = 4.56 years

<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>

H0( null hypothesis ) : u = 4.56

Ha : u ≠ 4.56

using test statistic

test statistic ; t = ( x' - u ) / std√ n

                        = ( 4.97 - 4.56 ) / 1.23 √ 61

                        = 2.60

let ∝ = 0.05 , critical value = -2.60 + 2.60

Hence we wont fail to accept  H0

This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05

3 0
3 years ago
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